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hoa [83]
3 years ago
7

How long does it usually take a hypothesis to become a theory

Physics
2 answers:
Ann [662]3 years ago
7 0

Answer:

If enough evidence accumulates to support a hypothesis, it moves to the next step (known as a theory) in the scientific method and becomes accepted as a valid explanation of a phenomenon.

insens350 [35]3 years ago
3 0

<u>Answer:</u>

Hypothesis is usually referred as an assumption or an observation made without much proof to support the statement. Hence scientists and experimental physicists uses hypothesis and perform experiments and observations to support the theory.

The hypothesis will get transformed into a theory only when there is enough evidence to support the cause and the science behind the set of events. It is dependent upon a number of scientific tests an hence it is not possible to define a time period. It may varies from years to forever (or never).

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What are the top three osha cited ladder violations
bonufazy [111]

Answer:

Explanation:

1. FALL PROTECTION-GENERAL REQUIREMENTS (29 CFR 1926.501) 6,010 VIOLATIONS

2. HAZARD COMMUNICATION (29 CFR 1910.1200). 3,671

3. SCAFFOLDING (29 CFR 1926.451). 2,813

6 0
3 years ago
A person is standing on and facing the front of a stationary skateboard while holding a construction brick. The mass of the pers
jek_recluse [69]

Answer:

0.74 m/s

Explanation:

From the question,

We apply the law of conservation of momentum,

Total momentum before collision = Total momentum after collision.

Since the skateboard, the person and the brick where stationary, therefore, the total momentum before collision is 0

0 = Total momentum after collision

(m+M)V + m'v = 0

Where m = mass of the  skateboard, M = mass of the person, m' = mass of the brick, V = recoil velocity of the person and the skateboard, v =  velocity of the brick

make V the subject of the equation above

V = -m'v/(m+M)................... Equation 1

Given: m = 4.10 kg, M = 68.0 kg, m' = 2.50 kg, v = 21.0 m/s.

Substitute these values into equation 1

V = -(2.5×21)/(68+2.5)

V = 52.50/70.5

V = 0.74 m/s

4 0
3 years ago
You are a member of an alpine rescue team and must get a box of supplies, with mass 3.00 kg , up an incline of constant slope an
Sever21 [200]

Answer:

v = 8.45 m/s

Explanation:

given,

mass  = 3 kg

angle = 30.0°

vertical distance = 3.3 m

μ = 0.06

according to conservation of energy

KE(loss) = PE(gain) + Work done (against\ friction)..............(1)

frictional Force

F_f = \mu N

F_f = \mu m g cos \theta

work against friction

W = F d

W = \mu m g cos \theta \times h l sin\theta

W = \dfrac{\mu m g \times h}{tan\theta}

Potential energy

PE = mgh

\dfrac{1}{2}mv^2= \dfrac{\mu mgh}{tan \theta}+ mgh

\dfrac{1}{2}v^2= \dfrac{0.06 \times 9.81 \times 3.3}{tan 30^0}+ 9.8\times 3.3

v = 8.45 m/s

the minimum speed is equal to 8.45 m/s

6 0
3 years ago
A proton initially has v=4.0i^−2.0j^+3.0k^ and then 4.0 s later has v=−2.0i^−2.0j^+5.0k^ (in meters per second). For that 4.0 s,
pishuonlain [190]

Answer:

a_{avg}=-1.5i+0.5k

1.58113883008\ m/s^2

-18.43^{\circ}\ or\ 161.57^{\circ}

Explanation:

u = 4.0i−2.0j+3.0k v = −2.0i−2.0j+5.0k

Average acceleration is given by

a=\dfrac{v-u}{t}\\\Rightarrow a=\dfrac{-2-4, -2+2, 5-3}{4}\\\Rightarrow a=-1.5i-0j+0.5k

a_{avg}=-1.5i+0.5k

The magnitude is

a_{avg}=\sqrt{(-1.5)^2+0.5^2}\\\Rightarrow a_{avg}=1.58113883008\ m/s^2

The magnitude is 1.58113883008\ m/s^2

The angle is

\theta=tan^{-1}\dfrac{a_z}{a_x}\\\Rightarrow \theta=tan^{-1}\dfrac{0.5}{-1.5}\\\Rightarrow \theta=-18.43^{\circ}\ or\ 161.57^{\circ}

The angle between a_{avg} and the positive direction of the x axis is -18.43^{\circ}\ or\ 161.57^{\circ}

4 0
3 years ago
A net force of 1.0N acts on a 4.0 kg object, initially at rest, for 4.0 seconds. What is the distance the object moves during th
Eva8 [605]
Use F=ma to solve for a=0.25m/s^2. Now to get distance you need to integrate this twice to get
x=(1/2)at^2. Plug in a and t to get
x=2m
8 0
3 years ago
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