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kykrilka [37]
4 years ago
11

Why does the hood of a car heat up after the car has been running for a while? A) According to the fourth law of thermodynamics,

the temperature of the other parts of the car increases due to the coolant used for the engine. B) According to the first law of thermodynamics, the hood of the car heats up using heat from the surroundings in-order to achieve thermal equilibrium with the engine. C) According to the second law of thermodynamics, not all energy from the burnt fuel is used to do work on the piston. It also produces heat which warms other parts of the car. D) According to the third law of thermodynamics, the increase in the velocity of the car changes the entropy of the tires. To balance this change, the temperature of the other parts is increased.
Physics
2 answers:
Svetlanka [38]4 years ago
6 0

Answer:

C) According to the second law of thermodynamics, not all energy from the burnt fuel is used to do work on the piston. It also produces heat which warms other parts of the car.  

Explanation:

A) According to the fourth law of thermodynamics, the temperature of the other parts of the car increases due to the coolant used for the engine.  

B) According to the first law of thermodynamics, the hood of the car heats up using heat from the surroundings in-order to achieve thermal equilibrium with the engine.  

C) According to the second law of thermodynamics, not all energy from the burnt fuel is used to do work on the piston. It also produces heat which warms other parts of the car.  

D) According to the third law of thermodynamics, the increase in the velocity of the car changes the entropy of the tires. To balance this change, the temperature of the other parts is increased.

gtnhenbr [62]4 years ago
3 0

Answer:

c

Explanation:

kuz i smrt

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Answer:

1299 N/m²

Explanation:

Applying,

P = ρgh............... Equation 1

Where P = pressure of water at the bottom of the container, ρ = density of water, h = height of water in the container, g = acceleration due to gravity.

but,

V = πr²h............ Equation 2

Where V = volume of water, r = radius of the container

make h the subject of the equation

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From the question,

Given: V = 200 liters, = 200000 cm³, r = 70 cm

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Substitute these values into equation 1

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