Quantity of gasoline needed by a car to run 800 miles = 30 gallons
Quantity of gasoline needed by a car to run 1 mile =
= 30 ÷ 800
= 0.0375 gallons
So , to run 1 mile a car would need = 0.0375 gallons of oil
To run 700 miles the quantity of gasoline needed =
= 700 × 0.0375
= 26.25 gallons of gasoline
Therefore , a car will use 26.25 gallons of gasoline on a trip of 700 miles .
Given that <span>v=234 3√p/w (cube root)
where </span><span>
p is the horsepower of the car and
w is the weight (in pounds) of the car
v is the velocity in miles per hour
p = 1311 hp
w = 2744 lb
substitute the given value to the equation to solve for the velocity
v = 234 </span><span>3√(1311 / 2744)
v = 183 miles per hour is the velocity of a car at the end of a drag race.</span>
Answer:
Step-by-step explanation: 3root5x^2 + 25x - 10root5 = 0
3xroot5 + 25x - 10root5 = 0 [ root x^2 = x]
28x root5 = 10 root5 [ -10root5 turns to 10 root5 when transferred to RHS]
28x root 5/root5 =10
28x=10
x = 10/28
x = 0.35
Hope it helped u,
pls mark as the brainliest
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Answer:y = 3x + 2
Step-by-step explanation: y = mx + b
Where m is the slope and b is the y-intercept.
Answer: y = -4x-9
Step-by-step explanation:
parallel slope means it's the same slope as the given equation
y+1=-4(x+2)
y+1 = -4x-8
y = -4x-9
