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2 years ago

What is the decimal multiplier to increase by 1.5 pls do the step by step explanation ineed help

Mathematics

1 answer:

satela [25.4K]2 years ago

5 0

Answer:

Just an explanation so you can understand

Step-by-step explanation:

To increase, or decrease a number N, by a percentage X% we multiply N by a percentage multiplier (often just called multiplier).

We can calculate any percentage increase, or decrease, in three steps:

Step 1: write X% in decimal form. Remember, this is done by moving the number X back two decimal places.

Example: 5%=0.05, 12%=0.12, ... .

Step 2: Calculate the percentage multiplier by adding, or subtracting, the decimal found in step 1 to, or from, 1

For percentage increases: add the decimal to 1.

For percentage decreases: subtract the decimal from 1.

Step 3: multiply the number N by the multiplier, found in Step 2.

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Answer:

Step-by-step explanation:

We'll take this step by step. The equation is

$8-3\sqrt[5]{x^3}=-7$

Looks like a hard mess to solve but it's actually quite simple, just do one thing at a time. First thing is to subtract 8 from both sides:

$-3\sqrt[5]{x^3}=-15$

The goal is to isolate the term with the x in it, so that means that the -3 has to go. Divide it away on both sides:

$\sqrt[5]{x^3}=5$

Let's rewrite that radical into exponential form:

$x^{\frac{3}{5}}=5$

If we are going to solve for x, we need to multiply both sides by the reciprocal of the power:

$(x^{\frac{3}{5}})^{\frac{5}{3}}=5^{\frac{5}{3}}$

On the left, multiplying the rational exponent by its reciprocal gets rid of the power completely. On the right, let's rewrite that back in radical form to solve it easier:

$x=\sqrt[3]{5^5}$

Let's group that radicad into groups of 3's now to make the simplifying easier:

$x=\sqrt[3]{5^3*5^2}$ because the cubed root of 5 cubed is just 5, so we can pull it out, leaving us with:

$x=5\sqrt[3]{5^2}$ which is the same as:

$x=5\sqrt[3]{25}$

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