Answer:
c) 8 protons 10 electrons
Because there would usually be 8 of both, but in this case there has to be 2 more electrons to give it the ²⁻ charge
I will say this is True….?
Hey there!
Molar mass NaCl = 58.44 g/mol
number of moles:
n = m / mm
n = 15.0 / 58.44
n = 0.2566 moles of NaCl
Volume in Kg :
50.0 g / 1000 => 0.05 Kg
Therefore :
Molality = moles of solute / volume
Molatity = 0.2566 / 0.05
Molality = 5.132 mol/kg
You need the solubility of the LiCl in water at 20°C.
The solubilities are shown in tables. Many books contain those tables. You have to make sure that the solubility is shown in the same solvent and at the same temperature that you are going to prepare the solution.
In this case the solubility of LiCl in water at 20°C is 83.05 g of LiCl in 100 g of H2O. Check if your book and your teacher work with the same value.
Using 8.05 g LiCl / 100 g of water you get:
300 g of water * 83.05 g LiCl / 100 g of water = 249.15 g of LiCl.
Answer: 249.15 g of LiCl