Answer:
D) HCl(aq)
Explanation:
A homogeneous mixture can be defined as any liquid, solid or gaseous mixture which has an identical or uniform composition and properties throughout any given sample of the mixture. In Chemistry, all solutions are considered to be a homogeneous mixture.
In this scenario, the chemical formula which represents a homogeneous mixture is aqueous hydrogen chloride, HCl(aq). The aqueous hydrogen chloride is a homogeneous mixture of water and hydrogen chloride. This ultimately implies that, aqueous hydrogen chloride HCl(aq) is a solution of hydrogen chloride in water and it is commonly referred to as Hydrochloric acid.
Given by the chemical equation;
Answer:
0.85 mole of PBr3.
Explanation:
We'll begin by writing the balanced equation for the reaction. This is given below:
3Br2 + 2P —> 2PBr3
From the balanced equation above,
3 moles of Br2 reacted to produce 2 moles of PBr3.
Therefore, 1.27 moles of Br2 will react to produce = (1.27 x 2)/ 3 = 0.85 mole of PBr3.
Therefore, 0.85 mole of PBr3 is produced by the reaction.
Answer:
<u><em>Arrhenius Acid:</em></u>
According to Arrhenius concept, Acids are proton donors.
Since H₂SO₄ have a proton (H⁺ ion) and it can donate it to be made a sulphate ion, So it is an Arrhenius acid.
See the following reaction =>
<u><em>H₂SO₄ + H₂O => HSO₄ + H₃O⁺</em></u>
<u><em>Arrhenius Base:</em></u>
An Arrhenius base is a a proton acceptor.
KOH accepts the proton to to made to KOH₂ and a proton acceptor.
See the following reaction =>
<u><em>KOH + H₂o => KOH₂ + OH⁻</em></u>
<u><em></em></u>
Answer:
0.718L of 0.81M HCl are required
Explanation:
Based on the reaction:
Cd(s)+2HCI(aq) → H2(g)+CdCl2(aq)
<em>1 mol of Cd reacts with 2 moles of HCl</em>
<em />
To solve this question we must, as first, find the moles of Cd. With the moles of Cd we can find the moles of HCl needed to react completely with the Cd. With the moles and the molarity we can find the volume:
<em>Moles Cd -Molar mass: 112.411g/mol-:</em>
32.71g * (1mol / 112.411g) = 0.2910 moles Cd
<em>Moles HCl:</em>
0.2910 moles Cd * (2 moles HCl / 1mol Cd) =
0.5820 moles HCl
<em>Volume:</em>
0.5820 moles HCl * (1L / 0.81moles) =
<h3>0.718L of 0.81M HCl are required</h3>
