Answer:
Molecules that have the same chemical formula (same numbers of each atom) but different three-dimensional shapes are called <u>Stereoisomers</u>.
Explanation:
Stereoisomerism is a phenomenon in which molecules have same molecular formula but have different arrangement of atoms or group of atoms in space. It is further classified as;
i) Geometrical Isomerism:
In this class of isomerism the groups or atoms about the double bond occupies different region in space. It is also called as <em>cis-trans </em>isomerism.
ii) Optical Isomerism:
In this class the molecules having same molecular formula differ in their interaction towards plane polarized light.
The full ionic chemical balanced equation for CuCl2 and (NH4)2SO4 is 2(NH4)Cl + CuSO4.
Explanation:
The full ionic chemical balanced equation for CuCl2 and (NH4)2SO4 is
CuCl2 + (NH4)2SO4 ⇔ 2(NH4)Cl + CuSO4.
Here the left side one's are reactants i.e.,CuCl2 and (NH4)2SO4.
The right siders are products i.e.,(NH4)Cl and CuSO4.
The complete ionic equation is used to include both chemical species as well as spectator ions. It is used to indicate which of the reactants and products in the equation exists primarily as ions in aqueous solution.
It is nothing but a chemical equation in which electrolytes which are soluble in water are formed as dissociated ions.
The above chemical reaction is double displacement reaction.
Answer :
(a) The rate of 
formed is, 0.066 M/s
(b) The rate of 
formed is, 0.033 M/s
Explanation : Given,
![\frac{d[NO]}{dt}](https://tex.z-dn.net/?f=%5Cfrac%7Bd%5BNO%5D%7D%7Bdt%7D)
= 0.066 M/s
The balanced chemical reaction is,
The rate of disappearance of 
= ![-\frac{1}{2}\frac{d[NO]}{dt}](https://tex.z-dn.net/?f=-%5Cfrac%7B1%7D%7B2%7D%5Cfrac%7Bd%5BNO%5D%7D%7Bdt%7D)
The rate of disappearance of = ![-\frac{d[O_2]}{dt}](https://tex.z-dn.net/?f=-%5Cfrac%7Bd%5BO_2%5D%7D%7Bdt%7D)
The rate of formation of = ![\frac{1}{2}\frac{d[NO_2]}{dt}](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B2%7D%5Cfrac%7Bd%5BNO_2%5D%7D%7Bdt%7D)
As we know that,
= 0.066 M/s
(a) Now we have to determine the rate of formed.
![\frac{1}{2}\frac{d[NO_2]}{dt}=\frac{1}{2}\frac{d[NO]}{dt}](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B2%7D%5Cfrac%7Bd%5BNO_2%5D%7D%7Bdt%7D%3D%5Cfrac%7B1%7D%7B2%7D%5Cfrac%7Bd%5BNO%5D%7D%7Bdt%7D)
![\frac{d[NO_2]}{dt}=\frac{d[NO]}{dt}=0.066M/s](https://tex.z-dn.net/?f=%5Cfrac%7Bd%5BNO_2%5D%7D%7Bdt%7D%3D%5Cfrac%7Bd%5BNO%5D%7D%7Bdt%7D%3D0.066M%2Fs)
The rate of formed is, 0.066 M/s
(b) Now we have to determine the rate of molecular oxygen reacting.
![-\frac{d[O_2]}{dt}=-\frac{1}{2}\frac{d[NO]}{dt}](https://tex.z-dn.net/?f=-%5Cfrac%7Bd%5BO_2%5D%7D%7Bdt%7D%3D-%5Cfrac%7B1%7D%7B2%7D%5Cfrac%7Bd%5BNO%5D%7D%7Bdt%7D)
![\frac{d[O_2]}{dt}=\frac{1}{2}\times 0.066M/s=0.033M/s](https://tex.z-dn.net/?f=%5Cfrac%7Bd%5BO_2%5D%7D%7Bdt%7D%3D%5Cfrac%7B1%7D%7B2%7D%5Ctimes%200.066M%2Fs%3D0.033M%2Fs)
The rate of formed is, 0.033 M/s
Given that,
Work done by the system = 125 J
Energy released when it cools down = 438 J
To find,
The change in internal energy.
Solution,
As heat is released by the system, Q = -438 J
Work done by the system, W = -125 J
Using the first law of thermodynamics. The change in internal energy is given by :
So, the change in internal energy is 563 J.
