An average is just the total attendance numbers / the number of performances.
Let's let the number of people in the third show be equal to x so we can write this as a formula, it's easier to read. x is just "some number we don't know"
The average is
Average=Total attendance/3
So
3000=(2580+2920+x)/3
So let's multiply by that 3 on both sides, make x easier to find
Average*3=2580+2920+x ( * means multiplied)
The average is 3000
So
2580+2920+x=3000*3
2580+2920+x=9000
Then we subtract those other attendances to get x on its own.
x=9000-2580-2920
x=3500
Answer:
I have got an answer it is false for explanation go to picture
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The answer to your question is 1/3
Answer:
$10
Step-by-step explanation:
The hardcover books are $12 each which would be $60 out of the $100. There are four more paperbacks meaning they would be $10 each and cost $40 total.
I hope this helped!!! :)
Answer:
896
Step-by-step explanation:
Let's talk first about how many 3 digit numbers there are. The first 3 digit number is 100 and the last is 999. So there are 999-100+1 numbers that are 3 digits long. That simplifies to 900.
Now let's find how many of those have a sum for the digits being 1, then 2 ? Then take that sum away from the 900 to see how many 3 digit numbers have the sum of their digits being more than 2.
3 digit numbers with sum of 1:
The first and only number is 100 since 1+0+0=1.
We can't include 010 or 001 because these aren't really three digits long.
3 digit numbers with sum of 2:
The first number is 101 since 1+0+1=2.
The second number is 110 since 1+1+0=2.
The third number is 200 since 2+0+0=2.
That's the last of those. We could only use 0,1, and 2 here.... Anything with a 3 in it would give us something larger than or equal to 3.
So there are 900-1-3 numbers who are 3 digits long and whose sum of digits is greater than 2.
This answer simplifies to 896.
