Let A( t , f( t ) ) be the point(s) at which the graph of the function has a horizontal tangent => f ' ( t ) = 0.
But, f ' ( x ) = [ ( x^2 ) ' * ( x - 1 ) - ( x^2 ) * ( x - 1 )' ] / ( x - 1 )^2 =>
f ' ( x ) = [ 2x( x - 1 ) - ( x^2 ) * 1 ] / ( x - 1 )^2 => f ' ( x ) = ( x^2 - 2x ) / ( x - 1 )^2;
f ' ( t ) = 0 <=> t^2 - 2t = 0 <=> t * ( t - 2 ) = 0 <=> t = 0 or t = 2 => f ( 0 ) = 0; f ( 2 ) = 4 => A 1 ( 0 , 0 ) and A 2 ( 2 , 4 ).
Answer:
28
Step-by-step explanation:
In this question, the units are just the number of boxes/grid-squares. So count how many boxes they have to walk between each step. You start at the top left location, and go around to all of them counting the boxes they pass.
they should all add up to 28 boxes, or 28 units!
Answer: Sara multiplied by 3 when she should have multiplied by 8.
Step-by-step explanation:
21 : 7*8
7*8 = 56
21 : 56
The simplest form of this ratio is 3 : 8
Answer:
Multiply 1240 by 1.15 to get 1426 students enrolled this year.
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