Answer:
22.95 (Addition)
Step-by-step explanation:
Add the numbers
Add $5.35 + $17.50
Answer = 22.95
How did we get it? ( Added the numbers)
Have a good day :D
Step-by-step explanation:
<u>Permutations</u>:
n<em>P</em><em> </em>r = n!/(n + r)!
<u>Combinations</u>:
<em>nCr</em> = n!/(n - r)!r!
c - combination
p - permutations
Since in both the problems they are looking for different groups, it is a combination problem. the order in which the people were selected in each group is not important, what is required are different groups.
<u>A.</u>
n = 51
r = 3
51<em>C</em><em> </em>3 = 51! / ((51 - 3) ×3!)
<em>51C</em><em>3</em><em> </em><em>=</em><em> </em><em>2</em><em>0</em><em> </em><em>8</em><em>2</em><em>5</em><em> </em>groups
<u>OR:</u>
<em><u>B</u></em><em><u>.</u></em>
As your sample size grows larger, the n - 1 adjustment for the standard deviation has a smaller impact on the estimates of standard deviation.
<u>Step-by-step explanation:</u>
The average (mean) of sample's distribution seems to be the same as the distribution mean at which samples were taken. The means of mean distribution will not change. However, the standard deviations for the samples mean is the standard deviations of the primary distribution divided by square roots of the samples size.
The standard deviations of means decreases as the samples size increases. Likewise, when the samples size decreases, the standard deviations for the samples mean increases. So, there is a little impact on standard deviations estimation when sample size increases.
