Answer:
D) the carbon with the low-energy phosphate on it in 1,3 BPG is labeled.
Explanation:
Glycolysis has 2 phase (1) preparatory phase (2) pay-off phase.
<u>(1) Preparatory phase</u>
During preparatory phase glucose is converted into fructose-1,6-bisphosphate. Till this time the carbon numbering remains the same i.e. if we will label carbon at 6th position of glucose, its position will remian the same in fructose-1,6-bisphosphate that means the labeled carbon will still remain at 6th position.
When fructose-1,6-bisphosphate is further catalyzed with the help of enzyme aldolase it is cleaved into two 3 carbon intermediates which are glyceraldehyde 3-phosphate (GAP) and dihyroxyacetone phosphate (DHAP). In this conversion, the first three carbons of fructose-1,6-bisphosphate become carbons of DHAP while the last three carbons of fructose-1,6-bisphosphate will become carbons of GAP. It simply means that GAP will acquire the last carbon of fructose-1,6-bisphosphate which is labeled. Now the last carbon of GAP which has phosphate will be labeled.
<u>(2) Pay-off phase</u>
During this phase, GAP is dehydrogenated into 1,3-bisphosphoglycerate (BPG) with the help of enzyme glyceraldehyde 3-phosphate dehydrogenase. This oxidation is coupled to phosphorylation of C1 of GAP and this is the reason why 1,3-bisphosphoglycerate has phosphates at 2 positions i.e. at position 1 in which phosphate is newly added and position 3rd which already had labeled carbon.
It is pertinent to mention here that<u> BPG has a mixed anhydride and the bond at C1 is a very high energy bond.</u> In the next step, this high energy bond is hydrolyzed into a carboxylic acid with the help of enzyme phosphoglycerate kinase and the final product is 3-phosphoglycerate. Hence, the carbon with low energy phosphate i.e. the carbon at 3rd position remains labeled.
Atoms will combine with each in order to become more chemically stable by sharing electron and Compounds are formed between two atoms that have chemical bond that links them together.
In order for molecules and crystals to form, atoms or ions must maintain a long-lasting attraction to one another. Ionic and covalent bonds are formed by the sharing of electrons, while ionic bonds are formed by the electrostatic attraction between two oppositely charged ions. There are "strong bonds" or "primary bonds" like covalent, ionic, and metallic bonds as well as "weak bonds" or "secondary bonds" like dipole-dipole interactions, the London dispersion force, and hydrogen bonding. The strength of chemical bonds varies greatly. By sharing or transferring electrons between the involved atoms, strong chemical bonds are created.
Since opposing electric charges attract, the positively charged protons inside a nucleus and the negatively charged electrons that surround it are drawn to one another. Placing an electron between them
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Answer:
The correct answer is <em>d. The nucleoside triphosphates have the sugar deoxyribose; ATP has the sugar ribose.</em>
Explanation:
The nucleoside triphosphates are components of DNA (deoxyribonucleic acid) so they are composed by a nitrogenous base (adenine, guanine, thymine or cytosine) and a deoxyribose sugar. In contraposition, ATP (adenosine triphosphate) is composed by the nitrogenous base adenine and a ribose sugar along with three phosphates groups. Unlike ribose, deoxyribose is a 5-carbon sugar which lack of an oxygen atom in C2 position.
1.50 atm(760 mmHg/1 atm)=1140 mmHg
