Answer:
Gold.
Explanation:
Because gold has a lower specific heat than aluminium.
Answer:
![K_c\text{ = }\frac{[O_2][H_2]\placeholder{⬚}^2}{[H_2O]\placeholder{⬚}^2}](https://tex.z-dn.net/?f=K_c%5Ctext%7B%20%3D%20%7D%5Cfrac%7B%5BO_2%5D%5BH_2%5D%5Cplaceholder%7B%E2%AC%9A%7D%5E2%7D%7B%5BH_2O%5D%5Cplaceholder%7B%E2%AC%9A%7D%5E2%7D)
Explanation:
Here, we want to write the equilibrium constant expression
To write this, we raise the concentrations of the reactants and products to the coefficient before them. These concentrations are represented by square brackets in which the chemical formula of the compound is placed
We place the representation of the products over that of the reactants
We have the expression written as follows:
![K_c\text{ = }\frac{[H_2]\placeholder{⬚}^2[O_2]}{[H_2O]\placeholder{⬚}^2}](https://tex.z-dn.net/?f=K_c%5Ctext%7B%20%3D%20%20%7D%5Cfrac%7B%5BH_2%5D%5Cplaceholder%7B%E2%AC%9A%7D%5E2%5BO_2%5D%7D%7B%5BH_2O%5D%5Cplaceholder%7B%E2%AC%9A%7D%5E2%7D)
Answer:
1. False
2. False
3. True
4. False
Explanation:
1. CBr4 is more volatile than CCl4 False
The molecular weight of CBr4 is is greater than the CCl4, therefore it has less tendency to escape to the gas phase. Also, the CBr4 has greater London dispersion forces compared to CCl4 since bromine is a larger atom than chlorine.
2. CBr4 has a higher vapor pressure at the same temperature than CCl4 False
For the same reasons as above, the vapor pressure of CBr4 is smaller than the vapor pressure of CCl4
3. CBr4 has a higher boling point than CCl4 True
Again, CBr4 having a molecular weight greater than CCl4 ( 331 g/mol vs 158.2 g/mol) is heavier and less volatile with a higher boiling point than CCl4.
4. CBr4 has weaker intermolecular forces than CCl4 False
Both molecules are non-polar because the dipole moments in C-Cl and C-Br bonds cancel in the tetrahedron. The only possible molecular forces are of the London dispersion type which are temporary and greater for larger atoms.
Answer:
When baking soda is mixed with vinegar, something new is formed. The mixture quickly foams up with carbon dioxide gas. If enough vinegar is used, all of the baking soda can be made to react and disappear into the vinegar solution.
Explanation:
