The balanced equation for the reaction between Mg and HCl is as follows Mg + 2HCl --> MgCl₂ + H₂ stoichiometry of HCl to H₂ is 2:1
number of HCl moles reacted - 0.400 mol/L x 0.100 L = 0.04 mol of HCl since Mg is in excess HCl is the limiting reactant number of H₂ moles formed - 0.04/2 = 0.02 mol of H₂
we can use ideal gas law equation to find the volume of H₂ PV = nRT where P - pressure - 1 atm x 101 325 Pa/atm = 101 325 Pa V - volume n - number of moles - 0.02 mol R - universal gas constant - 8.314 Jmol⁻¹K⁻¹ T - temperature in Kelvin - 0 °C + 273 = 273 K substituting these values in the equation
101 325 Pa x V = 0.02 mol x 8.314 Jmol⁻¹K⁻¹ x 273 K V = 448 x 10⁻⁶ m³ V = 448 mL therefore answer is c. 448 mL
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