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Ber [7]
4 years ago
13

A cell phone company relies on which kind of waves in order to provide service for its customers? ultraviolet waves infrared wav

es gamma rays microwaves
Physics
2 answers:
Greeley [361]4 years ago
6 0

Answer:

microwaves

Explanation:

Electromagnetic waves consist of waves of different wavelengths. Among the choices given, waves are ordered for increasing wavelengths as follows:

gamma rays --> ultraviolet waves --> infrared waves --> microwaves

So, microwaves are the waves with the longer wavelength among the given choices. This is the reason why they are used by the cell phone companies: in fact, since they have longer wavelengths, microwaves can travel longer distances without being absorbed by objects or obstacles, and so they are more reliable for broadcasting and telecommunications.

lara31 [8.8K]4 years ago
4 0

The correct answer is Microwaves

Explanation:

Among all the waves mentioned Micro-waves has the highest wavelength which helps it to transfer data along longer distances

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Jupiter's Great Red Spot is
pav-90 [236]

Answer:    

2 : A large storm

Explanation: I hope this helps

4 0
3 years ago
What mass of a material with density ρ is required to make a hollow spherical shell having inner radius r1 and outer radius r2?
krok68 [10]

Answer: m=\frac {\rho}{\frac{4}{3} \pi( (r_2)^{3} - (r_1)^{3}) }

It is given that:

Density of material =ρ

radius of inner spherical shell = r_1

radius of outer spherical shell=r_2

we know that the volume of sphere is \frac{4}{3}\pi r^{3}

Volume of the given spherical shell = \frac{4}{3}\pi( (r_2)^{3}-(r_1)^{3})

Then mass of the spherical shell can be calculate as:

Mass, m=density/ volume

m=\frac {\rho}{\frac{4}{3} \pi ((r_2)^{3} - (r_1)^{3}) }


6 0
3 years ago
Help pls lol and tysm
Zanzabum

Answer:

umm section 2 and 4

Explanation:

because at section 2 it starts and at section 4 it moves again and stops at 3.

7 0
3 years ago
A 7.77 kg mass is moving due west at 7.77 m/s. A second mass of 8.88 kg is moving due south at 8.88 m/s. What is the magnitude o
masya89 [10]

Answer:

8.362m/s

Explanation:

Given data

Mass m1= 7.77kg

Velocity v1= 7.77m/s

Mass m2= 8.88kg

Velocity v2= 8.88m/s

Apply the law of conservation of momentum for inelastic collision we have

m1v1+m2v2= (m+m2)V

7.77*7.77+ 8.88*8.88= (7.77+8.88)V

60.3729+78.8544= 16.65V

139.2273= 16.65V

Divide both sides by 16.65

V= 139.2273/16.65

V= 8.362m/s

Hence the final velocity is 8.362m/s

7 0
3 years ago
The fastest possible rate of rotation of a planet is that for which the gravitational force on material at the equator just bare
Brums [2.3K]

Answer:

6862.96871 seconds

Explanation:

M = Mass of Planet

G = Gravitational constant

r = Radius

\rho = Density

T = Rotation period

In this system the gravitational force will balance the centripetal force

G\frac{Mm}{r^2}=mr\omega^2

\omega=\frac{2\pi}{T}.

M=\rho v\\\Rightarrow M=\rho \frac{4}{3}\pi r^3

\\\Rightarrow G\frac{Mm}{r^2}=mr\left(\frac{2\pi}{T}\right)^2\\\Rightarrow \frac{G\rho \frac{4}{3}\pi r^3}{r^3}=\frac{4\pi^2}{T^2}\\\Rightarrow T=\sqrt{\frac{3\pi}{G\rho}}

Hence, proved

T=\sqrt{\frac{3\pi}{6.67\times 10^{-11}\times 3000}}\\\Rightarrow T=6862.96871\ s

The rotation period of the astronomical object is 6862.96871 seconds

7 0
3 years ago
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