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Serjik [45]
3 years ago
5

A runner circles the track exactly 2 times for distance of 800m. it takes 4.0min. what is her average speed in m/s? what is her

average velocity?
Physics
1 answer:
Sindrei [870]3 years ago
5 0

If the runner ends where she started, then her total displacement is \Delta x=0\,\mathrm m, which means her average velocity will be

\bar v=\dfrac{\Delta x}{\Delta t}=\dfrac{0\,\mathrm m}{4.0\,\mathrm{min}\cdot\frac{60\,\mathrm s}{1\,\mathrm{min}}=0\,\dfrac{\mathrm m}{\mathrm s}

The total distance she traversed, however, was \Delta d=800\,\mathrm m, which gives her an average speed of

\bar s=\dfrac{\Delta d}{\Delta t}=\dfrac{800\,\mathrm m}{4.0\,\mathrm{min}\cdot\frac{60\,\mathrm s}{1\,\mathrm{min}}=3.3\,\dfrac{\mathrm m}{\mathrm s}

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Explanation:

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d_B=D_A+d_a

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An 80-cm uniform 10-kg bar is resting on two scales, one at either end. A smaller 4-kg mass (m) is placed at a distance of d = 2
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Answer

given,

length of bar = 80 cm

mass of the bar = 10 kg

smaller mass = 4 kg

distance = 20 cm

s_1 + s_2 = 10 + 4

s_1 + s_2 = 14\ kg

taking moment about B

s_1 \times 0.8 - 10 \times 0.4 - 4 \times 0.6 = 0

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s_2 = 14 - s_1

s_2 = 14 - 8

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Low-cost energy. Although building nuclear power plants has a high initial cost, it’s relatively cheap to produce energy from them and they have low operating costs.

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The newly formed xenon nucleus is left in an excited state. Thus, when it decays to a state of lower energy a gamma ray is emitt
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Answer:3.87*10^-4

Explanation:

What is the decrease in mass, delta mass Xe , of the xenon nucleus as a result of this deca

We have been given the wavelength of the gamma ray, find the frequency using c = freq*wavelength.

C=f*lambda

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Then with the frequency, find the energy emitted using equation

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Plugging and computing all necessary numbers gives you

3.87*10^-4 u.

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