If the distance between two objects decrease and the masses of the objects remain the same, then the force of gravity between the two objects
<u>Answer:</u>
increases
Explanation:
The formula of gravitational force is given as:
F=G Mm/r^2
G = gravitational constant
M, m = Masses of two different objects in which the force is acting.
r = distance between both the objects.
As we can see from the formula that the force of gravity is inversely proportional to the square of the distance between both objects.
When the distance between both objects with the same masses decreases the gravitational force between them increases. Hence the correct answer is option B.
Illamends had the exact same answer from a similar question. Credit goes to her
Answer:
x = 7.62 m
Explanation:
First we need to calculate the weight of the rocket:
W = mg
we will use the gravity as 9.8 m/s². We have the mass (500 g or 0.5 kg) so the weight is:
W = 0.5 * 9.8 = 4.9 N
We know that the rocket exerts a force of 8 N. And from that force, we also know that the Weight is exerting a force of 4.9. From here, we can calculate the acceleration of the rocket:
F - W = m*a
a = F - W/m
Solving for a:
a = (8 - 4.9) / 0.5
a = 6.2 m/s²
As the rocket is accelerating in an upward direction, we can calculate the distance it reached, assuming that the innitial speed of the rocket is 0. so, using the following expression we will calculate the time which the rocket took to blast off:
y = vo*t + 1/2 at²
y = 1/2at²
Solving for t:
t = √2y/a
t = √2 * 20 / 6.2
t = √6.45 = 2.54 s
Now that we have the time, we can calculate the horizontal distance:
x = V*t
Solving for x:
x = 3 * 2.54 = 7.62 m
Answer:
The current in the motor in this case is 13.2 A
Explanation:
Given:
Resistance
5 Ω
Emf
V
Induced emf
V
When motor run at half speed due to load increased then induced emf is also reduced to half of its value
So new induced emf in our case is given by,
V

Where


A
Therefore, the current in the motor in this case is 13.2 A