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inn [45]
3 years ago
5

If the graphs of the linear equations in a system are the same line, what does that mean about the possible solution or solution

s of the system?
A.
There is exactly one solution.
B.
There is no solution.
C.
There are infinitely many solutions.
D.
The lines in a system cannot graph as the same line.
Mathematics
1 answer:
earnstyle [38]3 years ago
8 0

Answer:

C. infinitely many solutions

Step-by-step explanation:

every point of the line (or lines) is a solution.

so, infinitely many.

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What is the standard form of the equation of a circle that has its center at (-2,-3) and passes through the point (-2,0)?
rusak2 [61]
So the radius is from (-2, -3) to (-2, 0) which is a distance of 3The general form for the equation of a circle is:(x - h)^2 + (y - k)^2 = r^2, where the center is (h, k)Plug into the general equation

(x + 2)^2 + (y + 3)^2 = 3^2 \\ (x + 2)^2 + (y + 3)^2 = 9
6 0
3 years ago
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Carl wants to give away 1/3(fraction) of his baseball card collection.
alexandr1967 [171]

Answer:

1/3 / 1/3

1/3 x 3/1

= 1

Step-by-step explanation:

3 0
3 years ago
Eleven more than four times a number is 23
goblinko [34]
3 is the original number
You have to do reverse operations
23-11=12
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7 0
3 years ago
Please help me ASAP!Please this is due soon and i don't have all day.
Helga [31]

<u><em>Answer:</em></u>

Section 1: 5.59%

Section 2: -2.16%

Section 3: -10.82%

Section 4: -6.54%

Section 5: -2.16%

Section 6: 7.86%

<u><em>Explanation:</em></u>

<u>The formula to calculate the percent change in mass is given as:</u>

PercentChange = \frac{ChangeInMass}{StartingMass}*100=\frac{NewMass - OldMass}{OldMass}*100

<u>1- Section 1:</u>

Old mass = 7.83 g and New mass = 8.268 g

PercentChange = \frac{8.268-7.83}{7.83}*100 =5.59%

<u>2- Section 2:</u>

Old mass = 7.4 g and New mass = 7.24 g

PercentChange = \frac{7.24-7.4}{7.4}*100 =-2.16%

<u>3- Section 3:</u>

Old mass = 7.3 g and New mass = 6.51 g

PercentChange = \frac{6.51-7.3}{7.3}*100 =-10.82%

<u>4- Section 4:</u>

Old mass = 7.49 g and New mass = 7.0 g

PercentChange = \frac{7.0-7.49}{7.49}*100 =-6.54%

<u>5- Section 5:</u>

Old mass = 7.4 g and New mass = 7.24 g

PercentChange = \frac{7.24-7.4}{7.7.4}*100 =-2.16%

<u>6- Section 6:</u>

Old mass = 7.89 g and New mass = 8.51 g

PercentChange = \frac{8.51-7.89}{7.89}*100 =7.86%

Hope this helps :)

6 0
3 years ago
<img src="https://tex.z-dn.net/?f=5%5Csqrt%5B3%5D%7B2m%7D%20%3D20" id="TexFormula1" title="5\sqrt[3]{2m} =20" alt="5\sqrt[3]{2m}
ArbitrLikvidat [17]
The answer is M=32
Hope it helped
3 0
3 years ago
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