All categories

2 years ago

A room 9.5 m long and 6 m wide is surrounded by a verandah 1.25 m wide. Calculate the cost of

Mathematics

1 answer:

oksano4ka [1.4K]2 years ago

5 0

Answer:

Step-by-step explanation:

Area of room = 6×9.5=57m2

Area of room including verandah = 12×8.5=102m2

So area of verandah = 102−57=45m2

So cost of cementing the floor of this verandah = 45×80=3600rupees

You might be interested in

The number of patients treated at Dr. Martin's dentist office each day was recorded for nine days. These are the data: 6, 6, 6,

zmey [24]

Mean = 5.555555555.....
median = 6
mode = 6
range= 1

3 0

3 years ago

PLEASE SOMEONE HELP I TRULY DO NOT UNDERSTAND

IceJOKER [234]

Hi there!

$\large\boxed{f^{-1}(x) = \sqrt[3]{\frac{x+4}{9} } }$

$f(x) = 9x^{3} - 4$

Find the inverse by replacing f(x) with y and swapping the x and y variables:

$x = 9y^{3} - 4$

Isolate y by adding 4 to both sides:

$x + 4 = 9y^{3}$

Divide both sides by 9:

$\frac{x+4}{9}= y^{3}$

Take the cube root of both sides:

$y = \sqrt[3]{\frac{x+4}{9} }\\\\f^{-1}(x) = \sqrt[3]{\frac{x+4}{9} }$

7 0

2 years ago

A craftsman can sell 10 jewelry sets for $500 each. He knows

liraira [26]

Answer:15

Step-by-step explanation:

Given

Craftsman sell 10 Jewelry set for $500 each

For each additional set he will decrease the price by $ 25

Suppose he sells n set over 10 set

Earning $=\text{Price of each set}\times \text{no of set}$

Earning $=(500-25n)(10+n)$

$E=5000+500n-25n^2-250n$

differentiate to get the maximum value

$\frac{dE}{dn}=-50n+250$

Equate $\frac{dE}{dn}$ to get maximum value

$-50n+250=0$

$n=\frac{250}{50}$

$n=5$

Thus must sell 5 extra set to maximize its earnings.

5 0

2 years ago

What is the length of AC?

Eddi Din [679]

Your mom your mom your mom your dad your mom

5 0

2 years ago

Read 2 more answers

IF YOU DO THESE ILL LOVE YOU FOREVER AND ILL GIVE U BRAINLIEST!

juin [17]

Answer:

1. 6:10

2. 1:25

3. 11:15

4. 8:35

5. 4:30

6. 12:20

7. 3:55

8. 5:05

9. 10:40

4 0

2 years ago