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lisabon 2012 [21]
2 years ago
13

What is the answer of 42 / 4 = ?

Mathematics
2 answers:
Marizza181 [45]2 years ago
5 0
2 divided by 42 is 10.5 also just an FYI the “/” normally means division between two numbers; hence my answer :)
Yakvenalex [24]2 years ago
4 0

Answer:

42/4=10.5

Step-by-step explanation:

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Choose the property that justifies the following statement. If x = 2 and x + y = 3, then 2 + y = 3.
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3 years ago
Express the following numbers in standard form. [A] 509.78 [B] 0.0289 Can someone please help me ? I need to answer that questio
STALIN [3.7K]

Answer:

(A) 509.78

We need to move the decimal point after the first non-zero digit

So,

=> 5.0978 × 10² (Since the decimal point is moved two places to the left)

(B) 0.0289

Again after the first non-zero digit:

So, it becomes:

=> 2.89 × 10⁻² (Since the decimal point is moved 2 places to the right so it will be negative also)

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2 years ago
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In the illustration below, the three cube-shaped tanks are identical. The spheres in any given tank
fredd [130]

Answer:

1) Volume occupied by the spheres are equal therefore the three tanks contains the same volume of water

2) Amount \ of \, water \ remaining \ in \, the \ tank \ is \  \frac{x^3(6-\pi) }{6}

Step-by-step explanation:

1) Here we have;

First tank A

Volume of tank = x³

The  volume of the sphere = \frac{4}{3} \pi r^3

However, the diameter of the sphere = x therefore;

r = x/2 and the volume of the sphere is thus;

volume of the sphere = \frac{4}{3} \pi \frac{x^3}{8}= \frac{1}{6} \pi x^3

For tank B

Volume of tank = x³

The  volume of the spheres = 8 \times \frac{4}{3} \pi r^3

However, the diameter of the spheres 2·D = x therefore;

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For tank C

Volume of tank = x³

The  volume of the spheres = 64 \times \frac{4}{3} \pi r^3

However, the diameter of the spheres 4·D = x therefore;

r = x/8 and the volume of the sphere is thus;

volume of the spheres = 64 \times \frac{4}{3} \pi (\frac{x}{8})^3= \frac{x^3 \times \pi }{6}

Volume occupied by the spheres are equal therefore the three tanks contains the same volume of water

2) For the 4th tank, we have;

number of spheres on side of the tank, n is given thus;

n³ = 512

∴ n = ∛512 = 8

Hence we have;

Volume of tank = x³

The  volume of the spheres = 512 \times \frac{4}{3} \pi r^3

However, the diameter of the spheres 8·D = x therefore;

r = x/16 and the volume of the sphere is thus;

volume of the spheres = 512\times \frac{4}{3} \pi (\frac{x}{16})^3= \frac{x^3 \times \pi }{6}

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Amount of water remaining in the tank = Volume of tank - volume of spheres

Amount of water remaining in the tank = x^3 - \frac{x^3 \times \pi }{6} = \frac{x^3(6-\pi) }{6}

Amount \ of \ water \, remaining \, in \, the \ tank =  \frac{x^3(6-\pi) }{6}.

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3 years ago
Is there a relationship between the area and the perimeter of a rectangle
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I hope this helps :)
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A test is worth 140 points. Ten percent of those points are from one short-answer question. How many points is the short-
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The answer is 14. Since 140 x .10 = 14.
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