Answer:
Distance D = √ [(2 - x)^2 + (3 - 4x^3)^2].
Step-by-step explanation:
Use the distance formula:
D = √[(x2 - x1)^2 + (y2 - y1)^2].
So here it is
D = √[(2 - x)^2 + (4 - y)^2] where x,y is any point on the curve.
D = √[2 - x)^2 + (4 - (4x^3 + 1))^2]
D = √ [(2 - x)^2 + (3 - 4x^3)^2]
Answer:
5/6
Step-by-step explanation:
1 4/6-5/6=?
1 4/6=10/6
10/6-5/6=5/6
Answer:
≈0.487
Step-by-step explanation:
I think this is your full question right?
Jose surveyed the length of TV commercials (in seconds). Find, to 3 decimal places, the experimental probability that a randomly chosen TV commercial will last:
Length Frequency
0-19 17
20-39 38
40-59 19 20 to 39 seconds.
60+ 20 to 4
Here is my anwer:
experimental probability = relative frequency =
Total frequencies = 17 + 38 +18 + 4 = 78
P(20 to 39s) = 38/78 ≈0.487
A percentage can just be written as a decimal where 100% = 1.00
15% = 0.15
75.5 * 0.15 = 11.325
You just multiply.