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Vladimir79 [104]
3 years ago
7

Jim Jane Ann and Bill measure an object's length density mass and volume respectively with students measurement might be in lite

rs
Mathematics
2 answers:
malfutka [58]3 years ago
6 0

Answer:

Bill's

Step-by-step explanation:

done the topic

AnnyKZ [126]3 years ago
5 0

It would most likely be Bill's

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1 2/3 diveid by 4/5?
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Answer:

\frac{5}{3}

Step-by-step explanation:

If you would like me to explain let me know in the comments.

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Find the volume of the largest rectangular box in the first octant with three faces in the coordinate planes and one vertex in t
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Answer: The volume of largest rectangular box is 4.5 units.

Step-by-step explanation:

Since we have given that

Volume = xyz

with subject to x+2y+3z=9

So, let z=\dfrac{9-x-2y}{3}

So, Volume becomes,

V=xyz\\\\V=xy(\dfrac{9-x-2y}{3})\\\\V=\dfrac{9xy-x^2y-2xy^2}{3}

Partially derivative wrt x and y we get that

9-2x-2y=0\implies 2x+2y=9\\\\and\\\\9-x-4y=0\implies x+4y=9

By solving these two equations, we get that

x=3,y=\dfrac{3}{2}

So, z=\dfrac{9-x-2y}{3}=\dfrac{9-3-3}{3}=\dfrac{3}{3}=1

So, Volume of largest rectangular box would be

xyz=3\times \dfrac{3}{2}\times 1=\dfrac{9}{2}=4.5

Hence, the volume of largest rectangular box is 4.5 units.

4 0
3 years ago
In your random sample of 25 Chips Ahoy bags, you find a mean of 985 chips per bag, with a standard deviation of 10 chips. Run a
stealth61 [152]

Answer:

The p -value is less than 0.001.

Step-by-step explanation:

Given information:

Sample size = 25 chips

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Sample standard deviation = 10

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t=\frac{\overline{x}-\mu}{\frac{s}{\sqrt{n}}}

where,

\overline{x} is sample mean

μ is population mean.

s is sample standard deviation.

n is sample size.

The value of test statistic is

t=\frac{985-1000}{\frac{10}{\sqrt{25}}}

t=\frac{985-1000}{\frac{10}{\sqrt{25}}}

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The p-value is

p=2\times p(t

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4 years ago
According to the south carolina department of mental health web site, for every 200 u.s. women, the average number who suffer fr
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3 are expected to have the condition.

The expected value is the found by multiplying the probability by the number in the sample:

(1/200)×600
= (1/200)×(600/1)
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