Android<span>, </span>iOS<span>, Windows and </span>Blackberry<span> devices.</span>
Answer:
Here you go, alter this as you see fit :)
Explanation:
array = []
cnt = 0
while cnt < 11:
x = input("Enter a word: ")
array.append(x)
cnt += 1
y = input("Add another word?(Y/n): ")
if y.lower() == "n":
break
letter = input("\nChoose a letter: ")
if len(letter) != 1:
print("Error: too many characters")
quit()
for n in range(len(array)):
if letter.lower() in array[n].lower():
print(array[n], end= ",")
Answer:
60
Explanation:
Step 1: Write down the binary number:
111100
Step 2: Multiply each digit of the binary number by the corresponding power of two:
1x25 + 1x24 + 1x23 + 1x22 + 0x21 + 0x20
Step 3: Solve the powers:
1x32 + 1x16 + 1x8 + 1x4 + 0x2 + 0x1 = 32 + 16 + 8 + 4 + 0 + 0
Step 4: Add up the numbers written above:
32 + 16 + 8 + 4 + 0 + 0 = 60.
So, 60 is the decimal equivalent of the binary number 111100.
<span>What is Aggregate Demand equivalent to?
A. Real Output</span>