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Gre4nikov [31]
3 years ago
6

Write a program that sorts an array of 20 random numbersin the range from 0 through 1000.

Computers and Technology
1 answer:
Nuetrik [128]3 years ago
6 0

Answer:

#include<iostream>

#include<stdlib.h>

#include<time.h>

#include <algorithm>

using namespace std;

//main function program start from here

int main(){

   //seed the rand() function

   srand(time(NULL));

   //initialization

   int arr[20];

   //generate the 20 random number

  for(int i=0;i<20;i++){

   arr[i]=rand()%1000;   //store in array

  }

  sort(arr,arr+20); //sort the array by inbuilt function

  cout<<"The sorted array is."<<endl;

  //for display the each element in the array

  for(int i=0;i<20;i++){

   cout<<arr[i]<<endl;

  }

}

Explanation:

Create the main function and declare the array with size 20.

Take a for loop and generate the random number 20 times. For generating a random number, use the function rand();

rand() function which defines in the library stdlib.h, generate the random number within the range.

for example:

rand() % 20: generate the number between 0 to 19 ( Exclude 20).

for generating the random number different for every time, then we have to use srand() function and time function which defines in time.h library.

After that, store the number in the array.

Finally, take another loop and print all elements one by one.  

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The L-exclusion problem is a variant of the starvation-free mutual exclusion problem. We make two changes: as many as L threads
vladimir2022 [97]

Answer:

The solution is as follows.

class LFilters implements Lock {

int[] lvl;

int[] vic;

public LFilters(int n, int l) {

lvl = new int[max(n-l+1,0)];

vic = new int[max(n-l+1,0)];

for (int i = 0; i < n-l+1; i++) {

lvl[i] = 0;

}

}

public void lock() {

int me = ThreadID.get();

for (int i = 1; i < n-l+1; i++) { // attempt level i

lvl[me] = i;

vic[i] = me;

// rotate while conflicts exist

int above = l+1;

while (above > l && vic[i] == me) {

above = 0;

for (int k = 0; k < n; k++) {

if (lvl[k] >= i) above++;

}

}

}

}

public void unlock() {

int me = ThreadID.get();

lvl[me] = 0;

}

}

Explanation:

The code is presented above in which the a class is formed which has two variables, lvl and vic. It performs the operation of lock as indicated above.

6 0
3 years ago
Which elements are visible when a user opens a new PowerPoint presentation?
Mariulka [41]

Answer:

The only element visible is the presentation itself.

Explanation:

All of the other options, such as presenter's assistance, is hidden away from the projector, presentation device, etc. You are the only one that can see the window that shows what slide is next, presenter's notes, etc. <u>In other words, whatever you want the audience to see, that is only what they will see and nothing else.</u>

3 0
3 years ago
Read 2 more answers
#include
gavmur [86]

Answer:

See explaination

Explanation:

#include <fstream>

#include <iostream>

#include <iomanip>

using namespace std;

int main()

{

// Fill in the code to define payfile as an input file

ifstream payfile;

float gross;

float net;

float hours;

float payRate;

float stateTax;

float fedTax;

cout << fixed << setprecision(2) << showpoint;

// Fill in the code to open payfile and attach it to the physical file

// named payroll.dat

payfile.open("payroll.dat");

// Fill in code to write a conditional statement to check if payfile

// does not exist.

if(!payfile)

{

cout << "Error opening file. \n";

cout << "It may not exist where indicated" << endl;

return 1;

}

ofstream outfile("pay.out");

cout << "Payrate Hours Gross Pay Net Pay"

<< endl << endl;

outfile << "Payrate Hours Gross Pay Net Pay"

<< endl << endl;

// Fill in code to prime the read for the payfile file.

payfile >> hours;

// Fill in code to write a loop condition to run while payfile has more

// data to process.

while(!payfile.eof())

{

payfile >> payRate >> stateTax >> fedTax;

gross = payRate * hours;

net = gross - (gross * stateTax) - (gross * fedTax);

cout << payRate << setw(15) << hours << setw(12) << gross

<< setw(12) << net << endl;

outfile << payRate << setw(15) << hours << setw(12) << gross

<< setw(12) << net << endl;

payfile >> hours ;// Fill in the code to finish this with the appropriate

// variable to be input

}

payfile.close();

outfile.close();

return 0;

}

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Delvig [45]

Answer:

please translate

Thank you✌️

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Cindy Vindoolo logged on to her e-mail account to find that she had received 50 e-mails from a company called LifeCo that promis
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Answer:

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