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belka [17]
3 years ago
10

The management of a large store wants to enclose his yard with 1000 feet of fencing, using the building as one side. The area is

to be partitioned into 3 regions of equal area, using the same fencing. Find:
a. The function A(x) that describes the area of the yard
b. The domain of the function, in the context of the situation
c. The dimensions of the yard that will maximize the area of the yard
d. The maximum area.
Mathematics
1 answer:
aniked [119]3 years ago
7 0

Answer:

a.

day I s t he a newer ok ok ok

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Tickets to a play cost 8 dollars each write and expression that gives the ticket cost in dollars for a group of g girls and b bo
sladkih [1.3K]

Answer:

Step-by-step explanation:

8(B+G) OR 8B+8G

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denpristay [2]

Answear:

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40-50-60<br>Work out<br>2 × 1/7 -1 2/5<br>Give your answer in its simplest form.​
MAVERICK [17]

Answer:

the simplest form of the given expression is -1\frac{4}{35}

Step-by-step explanation:

Given;

2 \times  \frac{1}{7}  -  1\frac{2}{5}

The above expression can be simplified as follows;

2 \times  \frac{1}{7}  -  1\frac{2}{5} \\\\=\frac{2}{7} - \frac{7}{5} \\\\= l.c.m \ of \ 7 \ and \ 5 \ is \ 35\\\\= \frac{5(2) - 7(7)}{35} \\\\= \frac{10 - 49}{35} \\\\= -\frac{39}{35} \\\\= - 1\frac{4}{35}

Therefore, the simplest form of the given expression is -1\frac{4}{35}

5 0
3 years ago
A 30° 60° 90° triangle is shown below. Find the length of the side labeled y.
bulgar [2K]

Answer:

Part 1) y=3\ units

Part 2) The length of the hypotenuse is 6 units

Step-by-step explanation:

Part 1) we know that

In the right triangle of the figure

sin(60^o)=\frac{y}{2\sqrt{3}} ----> by SOH (opposite side divided by the hypotenuse)

solve for y

y=sin(60^o)2\sqrt{3}

Remember that

sin(60^o)=\frac{\sqrt{3}}{2}

substitute

y=(\frac{\sqrt{3}}{2})2\sqrt{3}

y=3\ units

Part 2)

Let

h ----> the length of the hypotenuse

we know that

In the right triangle of the figure

sin(45^o)=\frac{3\sqrt{2}}{h} ----> by SOH (opposite side divided by the hypotenuse)

h=\frac{3\sqrt{2}}{sin(45^o)}

Remember that

sin(45^o)=\frac{\sqrt{2}}{2}

substitute

h=3\sqrt{2}:\frac{\sqrt{2}}{2}

h=6\ units

7 0
3 years ago
Expressed powers are those that aref(x) = 5x + 3; g(x) = 6x - 5 Find f/g. (f/g)(x) = Quantity six x minus five divided by five x
allochka39001 [22]
Answer: <span>(f/g)(x) = Quantity five x plus three divided by six x minus five.domain {x|x ≠ Five over six. }

Explanation:

1) (f/g)(x) = f(x) / g(x)

2)

  f(x)         5x + 3
-------- = ------------
  g(x)        6x - 5

3) Since the division by 0 is not defined, the domain is restricted to 6x - 5 ≠ 0.

Therefore you must solve 6x - 5 = 0 to exclude the value of x for which the denominator becomes 0:

6 x - 5 = 0 => 6x = 5 => x = 5 / 6.

So, the domain is all x | x ≠ 5/6.
</span>
3 0
3 years ago
Read 2 more answers
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