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Aliun [14]
2 years ago
5

2. Determine whether each equation has one solution, no solution, or infinite solutions. Explain

Mathematics
1 answer:
ehidna [41]2 years ago
7 0
-2(x+5)=-6x+4(x-2)
-2x-10=-6x+4x-8
-2x+6x-4x=10-8
0x=2( unreasonable)
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PR and os are diameters of circle T. What is the
____ [38]

Answer:

100degrees

Step-by-step explanation:

Find the diagram attached

From the diagram

<PQT =<TRS = 40

Since the triangle STR is isosceles, here,

<TSR =<TRS = 40

Also the sum of angle in a triangle is 189, hence:

Arc SR+<TSR +<TRS = 18₩

ArcSR +40+40=180

ArcSR +80=180

ArcSR = 180-80

ArcSR = 100degrees

Hence the measure of SR is 100degrees

8 0
3 years ago
Please help! :))
denis23 [38]

Answer:

Check below

Step-by-step explanation:

Hi,

We're dealing with linear functions. f(x)=mx+b

We have here the first function.

g(x)=3x

That's a linear function, with slope, and no linear coefficient since

But on the other hand, the functions below, they all describe parallel lines, since their slope has the same value. I've changed the letters to make it easier the comprehension.

Even though each one has the same slope value, they have different non zero linear coefficients, {-6,-18,6,18}. Unlike, the first one

h(x)=3(9x-2) \rightarrow h(x)= 27x-6\\i(x)=9(3x-2)\rightarrow i(x)=27x-18\\j(x)=3(9x+2)\rightarrow j(x)=27x+6 \\k(x)=9(3x+2)\rightarrow k(x)=27x+18\\

A possible solution would be adjusting any of these, whose operation would result in g(x)=3x, but

Like

y=9(\frac{3x}{9}-2)+18 =3x

4 0
3 years ago
For a normal distribution with μ=500 and σ=100, what is the minimum score necessary to be in the top 60% of the distribution?
STatiana [176]

Answer:

475.

Step-by-step explanation:

We have been given that for a normal distribution with μ=500 and σ=100. We are asked to find the minimum score that is necessary to be in the top 60% of the distribution.

We will use z-score formula and normal distribution table to solve our given problem.

z=\frac{x-\mu}{\sigma}

Top 60% means greater than 40%.

Let us find z-score corresponding to normal score to 40% or 0.40.

Using normal distribution table, we got a z-score of -0.25.

Upon substituting our given values in z-score formula, we will get:

-0.25=\frac{x-500}{100}

-0.25*100=\frac{x-500}{100}*100

-25=x-500

-25+500=x-500+500

x=475

Therefore, the minimum score necessary to be in the top 60% of the distribution is 475.

3 0
3 years ago
If 7x+3=24 what is the value of 5-4x?
sleet_krkn [62]
If 7x+3=24, that means x would be 3 so if you take 5-4x then that would be -7.
5 0
3 years ago
Read 2 more answers
The authors of a paper presented a correlation analysis to investigate the relationship between maximal lactate level x and musc
ArbitrLikvidat [17]

Answer:

a) Sample correlation coefficient, r = 0.7411

bi) test statistic, t = 4.102

bii) P-value = 0.000736

Step-by-step explanation:

a) The formula for the sample correlation coefficient is given by the formula:

r = \frac{S_{xy} }{\sqrt{S_{xx} S_{yy} }} }

S_{xx} = 2,648,130.357\\S_{yy} = 36.7376,\\S_{xy} = 7408.225

r = \frac{7408.225}{\sqrt{2648130.357*36.7376} }

r = 0.7511

b)

i) formula for the test statistic is given by the formula:

t = \frac{r\sqrt{n-1} }{\sqrt{1 - r^{2} } }

sample size, n = 4

t = \frac{0.7511\sqrt{14-1} }{\sqrt{1 - 0.7511^{2} } }

t = 4.102

ii) Degree of freedom, df = n -2

df = 14 -2

df = 12

The P-value is calculate from the degree of freedom and the test statistic using excel

P-value =(=TDIST(t,df,tail))

P-value = (=TDIST(4.1,12,1)

P-value = 0.000736

4 0
3 years ago
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