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2 years ago

Sarah stands at the corner of a rectangular field. If the field measures 180 m by 210 m, how far would Sarah need to walk to

Mathematics

1 answer:

Agata [3.3K]2 years ago

4 0

Answer:

30√85 or 276.5863 meters

Step-by-step explanation:

Use pythag theorom. a^2+b^2=c^2

180^2+210^2=c^2

c=276.5863

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Multiply and reduce to lowest form 1 2/5×1 7/10

LuckyWell [14K]

The answer is 2 19/50.
First of all you have to convert the mixed numbers into improper fractions. So, 1 2/5 is equal to 7/5 and 1 7/10 is equal to 17/10. Next you multiply the denominators by the denominators and multiply the numerator by the numerator. 7 times 17 is 119 and 5 times 10 is 50. So the fraction is 119/50. You convert the improper fraction into a mixed number, which is 2 19/50.

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2 years ago

Alex spent the summer helping out at his family

Setler79 [48]

Hey what school do you go too

The first one is yes he'll have enough

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2 years ago

Negative two and one-fourth divded by negative one and one-half

Bond [772]

Answer:

The answer is 3/2 or 1 1/2

Step-by-step explanation:

First, you have to make it as a improper fraction :

$- 2 \frac{1}{4}$

$= - \frac{( 2 \times 4) + 1}{4}$

$= - \frac{9}{4}$

$- 1 \frac{1}{2}$

$= - \frac{(1 \times 2) + 1}{2}$

$= - \frac{3}{2}$

Next, you can divide it by cutting out the common factor :

$- \frac{9}{4} \div - \frac{3}{2}$

$= - \frac{9}{4} \times - \frac{2}{3}$

$= - \frac{ 3}{2} \times - 1$

$= \frac{3}{2}$

$= 1 \frac{1}{2}$

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2 years ago

Solve the equation. plesse help.

Shtirlitz [24]

X = 2. 11 to the 4th power (2(2)) is equal to 14641.

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2 years ago

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One coin in a collection of 65 has two heads. The rest are fair. If a coin, chosen at random from the lot and then tossed, turns

geniusboy [140]

Answer:

P=1/65.

Step-by-step explanation:

We knaow that one coin in a collection of 65 has two heads. If a coin, chosen at random from the lot and then tossed, turns up heads 6 times in a row. We calculate the probability that it is the two-headed coin.

We calculate the number of possible combinations:

$C_1^{65}=\frac{65!}{1!(65-1)!}=65$

Number of favorable combinations is 1.

Therefore, the probability is

P=1/65.

6 0

2 years ago