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MaRussiya [10]
3 years ago
8

What is the slope of the line described by the equation 6X + 4y= 8

Mathematics
1 answer:
drek231 [11]3 years ago
8 0

Answer:

\large\boxed{\text{The slope}\ m=-\dfrac{3}{2}}

Step-by-step explanation:

The slope-intercept form of an equation of a line:

y=mx+b

m - slope

b - y-intercept

We have the equation of a line in the standard form:

6x+4y=8

Convert to the slope-intercept form:

6x+4y=8          <em>subtract 6x from both sides</em>

4y=-6x+8           <em>divide both sides by 4</em>

y=-\dfrac{6}{4}x+\dfrac{8}{4}

y=-\dfrac{3}{2}x+2

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We conclude that option 'C' i.e. 1/3x+1=2x-4 is the correct option.

Step-by-step explanation:

From the given graph, it is clear that the two lines meet at the point (3, 2).

In other words,

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The point of intersection between two lines is:

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Here:

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Now, checking the equation i.e. 1/3x+1=2x-4 to determine whether the equation contains the correct value of x-coordinate or not.

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Simplify

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subtract 2x from both sides

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Simplify

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Multiply both sides by 5

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Simplify

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Divide both sides by -5

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Simplify

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Therefore, the value of x = 3

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