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Rashid [163]
2 years ago
9

5 pounds 35 dollars how much for one pound

Mathematics
1 answer:
Tju [1.3M]2 years ago
3 0

Divide total dollars by total pounds:

$35 /5 = $7 per pound

Answer: $7

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A circle with circumference 20 has an arc with 72 degree central angle what is length of the arc
Debora [2.8K]

Answer:

<h2>4</h2>

Step-by-step explanation:

<em>Look at the picture.</em>

<em />

<em>At the beginning we have to calculate what part of the angle 360° is the given angle 75°.</em>

<em />\dfrac{75}{360}=75:360=0.2<em />

<em>The same part of the circumference of the circle is the arc defined by this central angle.</em>

The circumference <em>C = 20</em>.

Therefore

x=0.2\cdot20=4

4 0
2 years ago
Kronos Industries bought a desktop for $3,000. It is expected to depreciate at a rate of 10% per year. What will the value of th
kolbaska11 [484]

Answer:

$1968

Step-by-step explanation:

It will depreciate by 10% 4 times, which means that the result in the end will be <em>$3000 * (100% - 10%) * (100% - 10%) * (100% - 10%) * (100% - 10%)</em>, or, put simply, <em>x = $3000 * (0.9)⁴</em>.

Power: x = $3000 * 0.6561

Multiply: x = 1968.3 ≈ $1968

4 0
3 years ago
What is the area, in square meters, of the trapezoid below
ahrayia [7]

Answer:

114.12

Step-by-step explanation:

A = (a+b)/2 ×h

= (6.2 + 25.5)/2 ×7.2

=114.12

8 0
2 years ago
Which equation describes a parabola that opens left or right and whose vertex is at the point (h, v)?
nalin [4]
Vertex is at the point ( h , v ) 
The equation of a parabola is:
x = a ( y - v )² + h
Answer: B )
4 0
2 years ago
Read 2 more answers
*Asymptotes*<br> g(x) =2x+1/x-3 <br><br> Give the domain and x and y intercepts
Nataly [62]

Answer: Assuming the function is g(x)=\frac{2x+1}{x-3}:

The x-intercept is (\frac{-1}{2},0).

The y-intercept is (0,\frac{-1}{3}).

The horizontal asymptote is y=2.

The vertical asymptote is x=3.

Step-by-step explanation:

I'm going to assume the function is: g(x)=\frac{2x+1}{x-3} and not g(x)=2x+\frac{1}{x}-3.

So we are looking at g(x)=\frac{2x+1}{x-3}.

The x-intercept is when y is 0 (when g(x) is 0).

Replace g(x) with 0.

0=\frac{2x+1}{x-3}

A fraction is only 0 when it's numerator is 0.  You are really just solving:

0=2x+1

Subtract 1 on both sides:

-1=2x

Divide both sides by 2:

\frac{-1}{2}=x

The x-intercept is (\frac{-1}{2},0).

The y-intercept is when x is 0.

Replace x with 0.

g(0)=\frac{2(0)+1}{0-3}

y=\frac{2(0)+1}{0-3}  

y=\frac{0+1}{-3}

y=\frac{1}{-3}

y=-\frac{1}{3}.

The y-intercept is (0,\frac{-1}{3}).

The vertical asymptote is when the denominator is 0 without making the top 0 also.

So the deliminator is 0 when x-3=0.

Solve x-3=0.

Add 3 on both sides:

x=3

Plugging 3 into the top gives 2(3)+1=6+1=7.

So we have a vertical asymptote at x=3.

Now let's look at the horizontal asymptote.

I could tell you if the degrees match that the horizontal asymptote is just the leading coefficient of the top over the leading coefficient of the bottom which means are horizontal asymptote is y=\frac{2}{1}.  After simplifying you could just say the horizontal asymptote is y=2.

Or!

I could do some division to make it more clear.  The way I'm going to do this certain division is rewriting the top in terms of (x-3).

y=\frac{2x+1}{x-3}=\frac{2(x-3)+7}{x-3}=\frac{2(x-3)}{x-3}+\frac{7}{x-3}

y=2+\frac{7}{x-3}

So you can think it like this what value will y never be here.

7/(x-3) will never be 0 because 7 will never be 0.

So y will never be 2+0=2.

The horizontal asymptote is y=2.

(Disclaimer: There are some functions that will cross over their horizontal asymptote early on.)

6 0
3 years ago
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