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3 years ago

Study the mixture below and classify whether it is a solution, suspension or colloid.

Chemistry

1 answer:

sladkih [1.3K]3 years ago

8 0

Answer:

Mayonnaise - Colloid

Oil and Water - Suspension

salt and water - Solution (saline)

Need Explanation?

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5. An example of a muscle that is voluntarily controlled is a muscle that

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Answer:

A, Makes the leg move

Explanation:

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3 years ago

Describe the buffer capacity of the acetic acid buffer solution in relation to the addition of both concentrated and dilute acid

AysviL [449]

Answer:

The answer is in the explanation

Explanation:

Acetic acid, CH₃COOH, is a weak acid that will produce a buffer when its conjugate base, CH₃COO⁻, acetate ion, is added to the solution.

That is because a buffer is the mixture of a weak acid and its conjugate base or vice versa.

When an acid (HX) is added to the solution, the acetate ion will react producing acetic acid, thus:

CH₃COO⁻ + HX → CH₃COOH + X⁻

For this reason, the pH doesn't change abruptly because H⁺ ions are not produced.

Now, if a base (BOH) is added to the buffer, CH₃COOH will react producing acetate ion and water, thus:

CH₃COOH + BOH → CH₃COO⁻ + H₂O + B⁺.

In the same way, there are not produced free OH⁻ and the pH doesn't change significantly.

5 0

4 years ago

six different aqueous solutions are represented in the beakers below, and there total volumes are noted. (a) which solution has

wolverine [178]

The molarity of the solutions are as follows:

solution B has the highest molarity
solutions A, D and F have the same molarity
solutions A and C are mixed together have a lower molarity than B
solution F and D will have the same molarity
Volume of water required to be evaporated is 8.3 mL

<h3>What is molarity of a solution?</h3>

The molarity of a solution is the amount in moles of a substance present in a given volume of solution.

From the image of the solution given:

solution B has the highest molarity
solutions A, D and F have the same molarity
when solutions A and C are mixed, the resulting solution have a lower molarity than B
solution F and D will have the same molarity after 75 mL and 50 mL of water are added to each respectively
the molarity of B is 12/50 = 4/16.7. Volume of water required to be evaporated = 25 - 16.7 = 8.3 mL

Therefore, the molarity of the solutions depends on the moles of substance present per given volume of solution.

Learn more about molarity at: brainly.com/question/24305514

#SPJ1

6 0

2 years ago

se tienen 10 litros de nitrogeno gaseoso bajo una presion de 560 mm Hg. Determina el volumen del nitrogeno a una presion de 760

Dominik [7]

Answer:

working business city philadelphian

3 0

3 years ago

Part A

Roman55 [17]

These are two questions and two answers

Question 1.

Answer:

7.33 × 10 ⁻³ c

Explanation:

1) Data:

a) m = 9.11 × 10⁻³¹ kg

b) λ = 3.31 × 10⁻¹⁰ m

c) c = 3.00 10⁸ m/s

d) s = ?

2) Formula:

The wavelength (λ), the speed (s), and the mass (m) of the particles are reltated by the Einstein-Planck's equation:

λ = h / (m.s)

h is Planck's constant: h= 6.626×10⁻³⁴J.s

3) Solution:

Solve for s:

s = h / (m.λ)

Substitute:

s = 6.626×10⁻³⁴J.s / ( 9.11 × 10⁻³¹ kg × 3.31 × 10⁻¹⁰ m) = 2.20 × 10 ⁶ m/s

To express the speed relative to the speed of light, divide by c = 3.00 10⁸ m/s

s = 2.20 × 10 ⁶ m/s / 3.00 10⁸ m/s = 7.33 × 10 ⁻³

Answer: s = 7.33 × 10 ⁻³ c

Question 2.

Answer:

2.06 × 10 ⁻³⁴ m.

Explanation:

1) Data:

a) m = 45.9 g (0.0459 kg)

b) s = 70.0 m/s

b) λ = ?

2) Formula:

Macroscopic matter follows the same Einstein-Planck's equation, but the wavelength is so small that cannot be detected:

λ = h / (m.s)

h is Planck's constant: h= 6.626×10⁻³⁴J.s

3) Solution:

λ = h / (m.s)

Substitute:

λ = 6.626×10⁻³⁴J.s / ( 0.0459 kg × 70.0 m/s) = 2.06 × 10 ⁻³⁴ m

As you see, that is tiny number and explains why the wave nature of the golf ball is undetectable.

Answer: 2.06 × 10 ⁻³⁴ m.

5 0

3 years ago

Study the mixture below and classify whether it is a solution, suspension or colloid.​

Study the mixture below and classify whether it is a solution, suspension or colloid.