Answer:
.
Start color: yellowish-green.
End color: dark purple.
Assumption: no other ion in the solution is colored.
Explanation:
In this reaction, chlorine gas 
oxidizes iodine ions 
to elemental iodide 
. At the same time, the chlorine atoms are converted to chloride ions 
.
Fluorine, chlorine, bromine, and iodine are all halogens. They are all found in the 17th column of the periodic table from the left. One similarity is that their anions are not colored. However, their elemental forms are typically colored. Besides, moving down the halogen column, the color becomes darker for each element.
Among the reactants of this reaction, is colorless. If there's no other colored ion, only the yellowish-green hue of would be visible. Hence the initial color of the reaction would be the yellowish-green color of .
Similarly, among the products of this reaction, is colorless. If there's no other colored ion, only the dark purple hue of would be visible. Hence the initial color of the reaction would be the dark purple color of .
At equivalence there is no more HA and no more NaOH, for this particular reaction. So that means we have a beaker of NaA and H2O. The H2O contributes 1 x 10-7 M hydrogen ion and hydroxide ion. But NaA is completely soluble because group 1 ion compounds are always soluble. So NaA breaks apart in water and it just so happens to be in water. So now NaA is broken up. The Na+ doesn't change the pH but the A- does change the pH. Remember that the A anion is from a weak acid. That means it will easily attract a hydrogen ion if one is available. What do you know? The A anion is in a beaker of H+ ions! So the A- will attract H+ and become HA. When this happens, it leaves OH-, creating a basic solution, as shown below.
Ho123 right I’m sorry of I’m wrong
The fourth option on Edgen, "two alcohol functional groups". You're welcome :)
B, C and E. In radioactive decay unstable atoms stabilize by releasing energy.
