Answer:
The width of 48 feet is represented by 12.8cm; the length represented by 1cm is 48/12.8 = 15/4 = 3.75 feet.
The length on the drawing is 3.2cm, which is exactly 1/4 of the width of 12.8cm; therefore the length of the actual parking lot is 48/4 = 12 feet.
.21 as a percentage is 21%
You can divide 7.98 by 21 then multiply by 100 which gives you an answer of 38.
Hope this helps :)
Answer:
8.95feet
Step-by-step explanation:
The set up is a right angled triangle where;
The camera's horizontal distance from the focus point = 26feet = Adjacent;
The height of the camera above the floor = Opposite = x
Angle of elevation = 19°
According to TOA in trig identity;
Tan theta = opp/adj
Tan 19 = x/26
x = 26tan 19
x = 26(0.3443)
X = 8.95feet
Hence the camera is placed at a height of 8.95feet above the floor
