Thermo-Electrochemical converter (UTEC) is a thermodynamic cycle that does not account for the Carnot Efficiency.
The Carnot cycle is a hypothetical cycle that takes no account of entropy generation. It is assumed that the heat source and heat sink have perfect heat transfer. The working fluid also remains in the same phase, as opposed to the Rankine cycle, in which the fluid changes phase. A practical thermodynamic cycle, such as the Rankine cycle, would achieve at most 50% of the Carnot cycle efficiency under similar heat source and heat sink temperatures.
<h3>What is Thermo-Electrochemical converter?</h3>
In a two-cell structure, a thermo-electrochemical converter converts potential energy difference during hydrogen oxidation and reduction to heat energy.
It employs the Ericsson cycle, which is less efficient than the Carnot cycle. In a closed system, it converts heat to electrical energy. There are no external input or output devices.
This means there will be no mechanical work to be done, as well as no exhaust. As a result, Carnot efficiency is not taken into account in this cycle. Carnot efficiency is accounted for by other options such as turbine and engine.
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Answer:
660V
Explanation:
V=IR
V=11×60
=660V
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Answer:
7.59Ns
Explanation:
Given parameters:
Force = 1360N
Time of contact = 5.85 x 10⁻³s
Unknown:
Impulse = ?
Solution:
The impulse of the ball is given as:
Impulse = Force x time
Impulse = 1360 x 5.85 x 10⁻³ = 7.59Ns
It would go to the positive charge im like 99% sure of that
Answer:
No.
Explanation:
We shall solve this problem by calculating the resolving power of eye for given wavelength
Resolving Power of eye = \frac{1.22\lambda }{D}
Where λ is wave length of light and D is diameter of eye.
λ is 600 nm and D is 3.5 mm . Put these values in the given formula
Resolving Power = \frac{1.22\times 600\times 10^{-9} }{3.5\times 10^{-3}}\\
=209.14 \times 10^{-6}radian
From the formula
Φ = \frac{L}{D}[/tex]
Where Ф is resolving power . If L be distance between two points that can be resolved at distance D. D is 6 km or 6000 m .
209.14 \times 10^{-6}=\frac{L}{6000}\\
L= 1.254 m
So minimum distance that can be resolved is 1.254 m.
