Table 1 shows a series of lonization Energies (IE) in kJ/mol.

The molarity of an aqueous sodium phosphate solution is 0.650 M. What is the molality of sodium ions present in this solution? T

netineya [11]

Answer:

molality of sodium ions is 1.473 m

Explanation:

Molarity is moles of solute per litre of solution

Molality is moles of solute per kg of solvent.

The volume of solution = 1 L

The mass of solution = volume X density = 1000mL X 1.43 = 1430 grams

The mass of solute = moles X molar mass of sodium phosphate = 0.65X164

mass of solute = 106.6 grams

the mass of solvent = 1430 - 106.6 = 1323.4 grams = 1.3234 Kg

the molality = $\frac{moles of solute}{mass of solvent in kg}=\frac{0.65}{1.323}= 0.491m$

Thus molality of sodium phosphate is 0.491 m

Each sodium phosphate of molecule will give three sodium ions.

Thus molality of sodium ions = 3 X 0.491 = 1.473 m

7 0

3 years ago

According to the following reaction, how many moles of carbon dioxide will be formed upon the complete reaction of 22.7 grams of

AnnZ [28]

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7 0

2 years ago

A gas fills up a container that has 2.5L has a pressure of 3.5 atm. If the gas gets transferred to a container that holds 4L, wh

disa [49]

New pressure = 2.5 x 3.5 / 4 = 2.185 atm

7 0

2 years ago

Samples with masses of 5.5 g 2.27 g and 0.8995 g are mixed together. The sum of the masses of the three

Nadusha1986 [10]

Answer:

$m=8.7g$

Explanation:

Hello,

In this case, it is widely known that when measurements with different significant figures are put under mathematical operations, the final result must be displayed with the same amount of significant figures of the shortest measurement, thus, due to the fact that 5.5 g has two significant figures only the result is consequently shown with two significant figures as well as shown down below:

$m=5.5g+2.27g+0.8995g\\\\m=8.6695g$