400$
Explanation:
In 1992, the price is 28000$ and 9600$ in 1996 so in 4 years the value the car lost is 18400$
Dividing 18400 by 4 years we get 4600 depreciation value per year.
Between 1996 and 1998 there is 2 years
So in 1998 the value of the car will be:
9600 (value in 1996) - 2x4600 = 400$
Answer:
The answer is (-3,7/2)
Step-by-step explanation:
I am a math teacher If you need any explanation you can communicate with me on Whats on this number +201557831028
Answer:
B
Step-by-step explanation:
edge2020
(b^4)^3
To simplify when something is raised to two different exponents, multiply the two exponents together:
4 * 3 = 12
You now have b^12.
The answer is D.
Answer:
<u><em></em></u>
Explanation:
Simulate (build a table) the growing of the number of pennies for some nights to figure out the pattern:
First night: 1 penny = 2⁰
Second night: 1 × 2 pennies = 2¹
Third night: 2 × 2 = 2²
Fourth nigth: 2² × 2 = 2³
nth night: 2ⁿ⁻¹
You want 2ⁿ⁻¹ ≥ 2,000,000,000
Which you solve in this way:
- n-1 log (2) ≥ log (2,000,000,000)
- n - 1 ≥ log (2,000,000,000) / log (2)
Since n is number of days, it is an integer number, so n ≥ 32.
Hence, she will have a total of more than $ 2 billion after 32 days.
You can prove that by calculating 2³² = 2,147,483,648.
