Percy probably made his estimate by rounding 0.58 per pound to 0.50, and rounding 2.03 for the price to 2.00. The 2.00/(0.50/lb) = 4 lb.
Percy's estimate is not unreasonable, but it is somewhat high (by more than 10%).
The cost, 0.58/lb, is closer to 0.6, a number that would cause Percy to estimate his purchase at 20/6 = 3 1/3 pounds.
When estimating, it is often useful to make an estimate of the error. This last estimate will be a little low, by about 3% due to the estimated cost and 1.5% due to the estimated total amount paid, for a total of about 4.5% low.
Answer:
B. -6 does not belong to the domain but belongs to the range of f(x).
Step-by-step explanation:
We have the function, .
So, the domain of the function is obtained when i.e.
That is, the domain is {x | x≥ 7}.
Now as we have,
→ → → → .
That is,
Thus, the range of the function f(x) is {y | y≤ 1}.
Thus, we can see that,
-6 does not belong to the domain but belongs to the range of f(x).
Answer:
0% chance
Step-by-step explanation:
Answer:
Q = -7/18
Step-by-step explanation:
Q = 1/6 - 5/9
Answer:
Correct option is (a).
Step-by-step explanation:
The dependent <em>t</em>-test (also known as the paired <em>t</em>-test or matched-samples <em>t</em>-test) compares the two means associated groups to conclude if there is a statistically significant difference amid these two means.
We use the paired <em>t</em>-test if we have two measurements on the same item, person or thing. We should also use this test if we have two items that are being measured with a unique condition.
For instance, an experimenter tests the effect of a medicine on a group of patients before and after giving the doses.
Or in case of testing the level of reading comprehension of students before and after the speed-reading class we use t-test for dependent means.
The assumptions of paired <em>t</em>-test are:
- The dependent variable that is tested should be continuous
- The observations are independent
- The dependent variable is normally distributed
- There should not be any outliers.
Since the data consists of matched pair, both the samples must be of the same size.
Thus, the correct option is (a).