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raketka [301]
2 years ago
10

Vapour-liquid equilibrium of a two-component ideal solution of trichloroethene (C2HCl3) and trichloromethane (CHCl3) is establis

hed at 25 °C. The mole fraction of CHCl3 in the vapour phase is 0.59. What is the mass fraction of C2HCl3 in the liquid phase? Round your answer to two significant figures.
The vapour pressures of trichloroethene and trichloromethane at 25 °C are:

Pvap,C2HCl3 = 73.0 mmHg

Pvap,CHCl3 = 199.1 mm Hg
Chemistry
1 answer:
riadik2000 [5.3K]2 years ago
4 0

Answer:

dajdajkwdanx

Explanation:

i need points

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What will be the end product for each electrode after electrolysis if the solution is concentrated aqueous sodium chloride ?​
Eddi Din [679]

Answer:

Cathode: Hydrogen gas

Anode: Chlorine gas

Explanation:

① Write down the ions present in the electrolyte

Cations: Na⁺, H⁺

Anions: Cl⁻ , OH⁻

② Decide which ions are preferentially discharged.

These are the factors:

For the discharge of cations,

- Reactivity series

(The lower the position of the cation in the reactivity series, the easier it is to be discharged)

For the discharge of anions,

- Concentration effect (look at this first)

(The more concentrated the ion, the easier for it to be discharged)

- If solution is not concentrated (dilute), look at the position of the anion on the electrochemical series.

(The lower the position of the anion on the electrochemical series, the easier of it to be discharged)

In this case:

For cations, H⁺ ions are selectively discharged at the cathode as its position is lower than Na⁺ in the reactivity series.

Anion: Cl⁻ ions, being more concentrated, are selectively discharged at the anode.

☆For electrolysis,

Cation at the cathode (-ve terminal)

Anion at the anode (+ve terminal)

In summary, here's what happened at each electrode:

<u>C</u><u>athode</u>

- H⁺ selectively discharged

- ionic half equation: 2H⁺ (aq) +2e⁻ → H₂ (g)

<u>Anode</u>

- Cl⁻ ions selectively discharged

- ionic half equation: 2Cl⁻ (aq) → Cl₂ (g) + 2e⁻

3 0
3 years ago
What volume does 18.0g of bromine occupy?
Varvara68 [4.7K]

Hey there!

Atomic mass Bromine ( Br ) = 79.9 u

Therefore:

79.9 g Br --------------- 22.4 L ( at STP )

18.0 g Br --------------- volume ??

Volume Br = 18.0 * 22.4 / 79.9

Volume Br = 403.2 / 79.9

Volume Br = 5.046 L

hope this helps!

4 0
3 years ago
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