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Shalnov [3]
3 years ago
11

ILL GIVE BRAINLIST............ have to answer all!!!!

Chemistry
1 answer:
7nadin3 [17]3 years ago
6 0
1 is seconds and meters m/s

2 is seconds and meters m/s^2

3 Newton kg/m

4 Kilograms

Hope this helps!
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Ben has a snack with a combination of raisins, chocolate pieces, and nuts. As he eats the snack, Ben picks out all of the raisin
erastova [34]

Answer:

Trail Mix

Explanation:

The best description for the snack that Ben is eating would be Trail Mix. This is a very common snack for hikers, hence the name, since it is very healthy and great for taking on hikes since it does not get affected by the sun. This snack was originally called GORP which stands for "good old raisins and peanuts" because the snack originally contained only raisins and peanuts. It has since changed to include various different ingredients such as a variety of nuts, chocolate pieces, dried fruit, cereal etc.

7 0
2 years ago
To what volume would you need to dilute 200 mL of a 5.85M solution of Ca(OH)2 to make it a 1.95M solution?
Blizzard [7]

Answer: 600 mL

Explanation:

Given that;

M₁ = 5.85 m

M₂ = 1.95 m

V₁ = 200 mL

V₂ = ?

Now from the dilution law;

M₁V₁ = M₂V₂

so we substitute

5.85 × 200 = 1.95 × V₂

1170 = 1.95V₂

V₂ = 1170 / 1.95

V₂ = 600 mL

Therefore final volume is 600 mL

8 0
3 years ago
WILL GIVE BRAINLIEST NO FAKE ANSWERS PLEASE!
AleksAgata [21]

Answer:

A) (3.2g)

Explanation:

Did you reposed this? Because I remember answering this

3 0
2 years ago
Read 2 more answers
What will the sun become when it dies
Nina [5.8K]

Answer:

It will become a red giant

Explanation:

When the sun runs out of its hydrogen fuel and the hydrogen atoms are combined together to make helium atoms, it expands into a red giant, which is made up of helium atoms and gases.

5 0
2 years ago
Does adding 1 mol of NaCl to 1 kg of water lower the vapor pressure of water to the same extent, a lesser extent, or a greater e
igor_vitrenko [27]

Answer:

Adding 1 mol of NaCl to 1 kg of water lower the vapor pressure of water <em><u>to the same extent</u></em>  by adding 1 mol of C_06H_{12}O_6 to 1 kg of water.

Explanation:

1) Moles of NaCl ,n_1=1 mol

Mass of water = m= 1 kg = 1000 g

Moles of water = n_2=\frac{1000 g}{18 g/mol}=55.55 mol

Vapor pressure of the solution = p

Vapor pressure of the pure solvent that is water = p_o=17.5 Torr

Mole fraction of solute(NaCl)= \chi_1=\frac{n_1}{n_1+n_2}

\frac{p_o-p}{p_o}=\frac{n_1}{n_1+n_2}

\frac{17.5 Torr-p}{17.5 Torr}=\frac{1 mol}{1 mol+55.55 mol}

p=17.19 Torr

The vapor pressure for the NaCl solution at 17.19 Torr.

2) Moles of sucrose ,n_1=1mol

Mass of water = m  = 1 kg = 1000 g

Moles of water = n_2=\frac{1000 g}{18 g/mol}=55.55 mol

Vapor pressure of the solution = p'

Vapor pressure of the pure solvent that is water = p_o=17.5 Torr

Mole fraction of solute ( glucose)= \chi_1=\frac{n_1}{n_1+n_2}

\frac{p_o-p}{p_o}=\frac{n_1}{n_1+n_2}

\frac{17.5 Torr-p}{17.5 Torr}=\frac{1 mol}{1 mol+55.55 mol}

p'=17.19 Torr

The vapor pressure for the glucose solution at 17.19 Torr.

p = p' = 17.19 Torr

Adding 1 mol of NaCl to 1 kg of water lower the vapor pressure of water to the same extent  by adding 1 mol of C_06H_{12}O_6 to 1 kg of water.

3 0
3 years ago
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