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Shalnov [3]
4 years ago
11

ILL GIVE BRAINLIST............ have to answer all!!!!

Chemistry
1 answer:
7nadin3 [17]4 years ago
6 0
1 is seconds and meters m/s

2 is seconds and meters m/s^2

3 Newton kg/m

4 Kilograms

Hope this helps!
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A 1.5-m 3 insulated rigid tank contains 2.7 kg of carbon dioxide at 100 kPa. Now paddle-wheel work is done on the system until t
Assoli18 [71]

Answer:

The entropy change of carbon dioxide = 0.719 kJ/k

Explanation:

Given:

1.5 m - 3 insulated rigid tank contains 2.7 kg of carbon dioxide at 100 kPa

The objective is to determine the entropy change of carbon dioxide

Formula used:

ΔS=

Solution:

On considering,

C_{P} =0.846 kJ/kg K\\C_V=0.657 kJ/kg k\\

ΔS=mc_{v} lu\frac{p_{2} }{P_{1} }

On substituting the values,

ΔS=2.7*0.657lu\frac{150}{100}

ΔS=0.719 kJ/k

4 0
3 years ago
Yoooooooooooooooooooooooooooooooooo
ira [324]
Hey, how are you.....
8 0
3 years ago
Read 2 more answers
Why are xrays used to probe the crystal structure of a material
ioda

Answer:

Because X-rays have wavelengths similar to the size of atoms

8 0
2 years ago
If a sample contains 70.0 % of the R enantiomer and 30.0 % of the S enantiomer, what is the enantiomeric excess of the mixture?
NeTakaya

Answer:

the enantiomeric excess of the mixture is 40%

Explanation:

The computation of the enantiomeric excess of the mixture is shown below:

As we know that

= |\frac{R - S}{R + S} |\times 100\\\\= |\frac{70 - 30}{70 + 30}| \times 100\\\\= 40\%

Hence, the enantiomeric excess of the mixture is 40%

3 0
3 years ago
Which of the following is not a conjugate acid-base pair? A) NH4+/NH3 B) H30-OH OC) H2SO3/HSO3 D) C2H302-/HC2H302
raketka [301]

Answer : The option (d) is not a conjugate acid-base pair.

Explanation :

According to the Bronsted Lowry concept, Bronsted Lowry-acid is a substance that donates one or more hydrogen ion in a reaction and Bronsted Lowry-base is a substance that accepts one or more hydrogen ion in a reaction.

Or we can say that, conjugate acid is proton donor and conjugate base is proton acceptor.

(a) The equilibrium reaction will be,

NH_4^++OH^-\rightleftharpoons NH_3+H_2O

In this reaction, NH_4^+/NH_3 are act as a conjugate acid-base.

(b) The equilibrium reaction will be,

H_3O^++OH^-\rightleftharpoons H_2O+H_2O

In this reaction, H_3O^+/OH^- are act as a conjugate acid-base.

(c) The equilibrium reaction will be,

H_2SO_3+OH^-\rightleftharpoons HSO_3^-+H_2O

In this reaction, H_2SO_3/HSO_3^- are act as a conjugate acid-base.

(d) The equilibrium reaction will be,

C_2H_3O_2^-+H_2O\rightleftharpoons HC_2H_3O_2+OH^-

In this reaction, C_2H_3O_2^-/HC_2H_3O_2 are act as a conjugate base-acid.

Hence, from this we conclude that, the option (d) is not a conjugate acid-base pair but it is a act as conjugate base-acid.

6 0
3 years ago
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