Answer:
10.54 L
Explanation:
Given that:-
Moles of = 1.00 moles
According to the given reaction:-
7 moles of oxygen gas reacts with 4 moles of ammonia
1 mole of oxygen gas reacts with moles of ammonia
Moles of ammonia = 0.5714 moles
Also, Given that:
Temperature = 850 °C
The conversion of T( °C) to T(K) is shown below:
T(K) = T( °C) + 273.15
So,
T₁ = (850 + 273.15) K = 1123.15 K
n = 0.5714 moles
P = 5.00 atm
Using ideal gas equation as:
where,
P is the pressure
V is the volume
n is the number of moles
T is the temperature
R is Gas constant having value = 0.0821 L atm/ K mol
Applying the equation as:
5.00 atm × V = 0.5714 moles ×0.0821 L atm/ K mol × 1123.15 K
⇒V = 10.54 L
<u>10.54 L of required.</u>
