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3 years ago

Which of these is a chemical property?

Chemistry

2 answers:

ankoles [38]3 years ago

7 0

Answer:

The second choice, or flammability.

Explanation:

The flammability of something is how easy it is for it to burn or ignite.

Marat540 [252]3 years ago

6 0

Answer:

The Answer in flammability

Explanation:

Both fire and the fire starter are chemicals therefore its B.

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£<br> 5.1.4 Quiz: Hydrocarbons<br><br> What is the name of this molecule?

lisov135 [29]

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3 years ago

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B) What happens to the soup water when elisya blows it harder with the soap bubble blower<br>

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3 years ago

Describe the environmental impacts that are involved during the design, research and development, and marketing phases of cell p

Debora [2.8K]

Answer:

joe mama

Explanation:

400 + 20 + 420

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3 years ago

Why is one side of the moon called "the dark side of the moon"?

dlinn [17]

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3 years ago

Find the molar enthalpy of formation for paraffin wax (C2H526)) given the following reaction

pogonyaev

Answer: The molar enthalpy of formation for paraffin wax is -2460.5 kJ

Explanation:

The balanced chemical reaction is,

$C_{25}H_{52}(g)+38O_2(g)\rightarrow 25CO_2(g)+26H_2O(g)$

The expression for enthalpy change is,

$\Delta H=\sum [n\times \Delta H_f(product)]-\sum [n\times \Delta H_f(reactant)]$

$\Delta H=[(n_{CO_2}\times \Delta H_{CO_2})+(n_{H_2O}\times \Delta H_{H_2O})]-[(n_{O_2}\times \Delta H_{O_2})+(n_{C_{25}H_{52}}\times \Delta H_{C_{25}H_{52}})]$

where,

n = number of moles

$\Delta H_{O_2}=0$ (as heat of formation of substances in their standard state is zero

Now put all the given values in this expression, we get

$-14800=[(25\times -393.5)+(26\times -285.5)]-[(38\times 0)+(1\times \Delta H_{C_{25}H_{52}})]$

$\Delta H_{C_{25}H_{52}}=-2460.5kJ/mol$

Therefore, the molar enthalpy of formation for paraffin wax is -2460.5 kJ

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3 years ago