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Alexeev081 [22]
3 years ago
13

Which of these is a chemical property?

Chemistry
2 answers:
ankoles [38]3 years ago
7 0

Answer:

The second choice, or flammability.

Explanation:

The flammability of something is how easy it is for it to burn or ignite.

Marat540 [252]3 years ago
6 0

Answer:

The Answer in flammability

Explanation:

Both fire and the fire starter are chemicals therefore its B.

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joe mama

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400 + 20 + 420

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Find the molar enthalpy of formation for paraffin wax (C2H526)) given the following reaction
pogonyaev

Answer: The molar enthalpy of formation for paraffin wax  is  -2460.5 kJ

Explanation:

The balanced chemical reaction is,

C_{25}H_{52}(g)+38O_2(g)\rightarrow 25CO_2(g)+26H_2O(g)

The expression for enthalpy change is,

\Delta H=\sum [n\times \Delta H_f(product)]-\sum [n\times \Delta H_f(reactant)]

\Delta H=[(n_{CO_2}\times \Delta H_{CO_2})+(n_{H_2O}\times \Delta H_{H_2O})]-[(n_{O_2}\times \Delta H_{O_2})+(n_{C_{25}H_{52}}\times \Delta H_{C_{25}H_{52}})]

where,

n = number of moles

\Delta H_{O_2}=0 (as heat of formation of substances in their standard state is zero

Now put all the given values in this expression, we get

-14800=[(25\times -393.5)+(26\times -285.5)]-[(38\times 0)+(1\times \Delta H_{C_{25}H_{52}})]

\Delta H_{C_{25}H_{52}}=-2460.5kJ/mol

Therefore, the molar enthalpy of formation for paraffin wax  is -2460.5 kJ

3 0
3 years ago
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