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Marrrta [24]
3 years ago
7

Write the equation of a line that goes through (1.-7) and has a slope of -5.

Mathematics
1 answer:
jekas [21]3 years ago
5 0
Line equation is
y - y1 = m * (x - x1)
y - (-7) = (-5) * ( x - 1)
y + 7 = -5x + 5
y + 5x + 2 = 0
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Paralell to y=4x-6 through (12,10)
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<u>ANSWER</u>

The line that is parallel to y=4x-6 through (12,10) is  y=2x-14.



<u>EXPLANATION</u>


The equation that is parallel to the line y=4x-6 has a slope that is equal to the slope of this line.

By comparing this equation to the general slope intercept form,

y=mx+c,this line has slope m=2.


Hence the line parallel to this line also has slope m=2.

Let y=mx+b be the equation of the line parallel to the line

y=4x-6

We can substitute m=2 to obtain;

y=2x+b


If the line passes through the point (12,10),then this point must satisfy its equation.


We substitute x=12 and y=10 to obtain;


10=2(12)+b


We this equation for b.


\Rightarrow 10=24+b


\Rightarrow 10-24=b


\Rightarrow -14=b


We substitute this value of  b=-14 in to y=2x+b to get;


y=2x+-14.


Hence the equation of the line that is parallel to y=4x-6 through (12,10) is  y=2x-14.




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