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ipn [44]
2 years ago
13

How many times greater is 3.9*10^-4 than 7.8 10^-6

Mathematics
2 answers:
Morgarella [4.7K]2 years ago
8 0

Answer:

50

Step-by-step explanation:

i am sure for that.it is so easy

Slav-nsk [51]2 years ago
6 0

Answer:

50 times greater than 7.8×10^-6

Step-by-step explanation:

\frac{3.9•10^{- 4}}{7.8•10^{- 6} \\\\\\ \frac{3.9}{7.8}•10^{- 4 -(- 6)} \\\\\\\ \frac{1}{2}•10^{- 4 + 6} \\\\\\ \frac{1}{2}•10^2 \\\\\\ \frac{1}{2}•100 \\\\\\ \frac{100}{2} \\\\\\ 50

I hope I've helped you.

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Fynjy0 [20]

The surface (call it S) is a triangle with vertices at the points

x=0,y=0\implies z=2\implies(0,0,2)

x=0,y=2\implies z=-2\implies(0,2,-2)

x=2,y=0\implies z=-8\implies(2,0,-8)

Parameterize S by

\vec s(u,v)=(1-v)(2,0,-8)+v\bigg((1-u)(0,2,-2)+u(0,0,2)\bigg)=(2-2v,2v-2uv,-8+6v+4uv)

with 0\le u\le1 and 0\le v\le1. Take the normal vector to S to be

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Then the flux of \vec F across S is

\displaystyle\iint_S\vec F(x,y,z)\cdot\mathrm d\vec S=\int_0^1\int_0^1\vec F(x(u,v),y(u,v),z(u,v))\cdot(\vec s_v\times\vec s_u)\,\mathrm du\,\mathrm dv

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serg [7]

Answer:

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Step-by-step explanation:

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