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deff fn [24]
2 years ago
11

The acceleration of an object is inversely proportional to its mass, so if you decrease its mass while keeping the net force the

same, the acceleration will increase.
true or false​
Physics
2 answers:
MaRussiya [10]2 years ago
5 0

Answer:

True

Explanation:

Since acceleration is inversely proportional to mass, decreasing mass will make the object lighter, and thus easier to speed up. So acceleration increases as mass decreases and vice versa

alekssr [168]2 years ago
3 0

Answer: TRUE                                                                        Explanation:Newton's second law of motion can be formally stated as follows: The acceleration of an object as produced by a net force is directly proportional to the magnitude of the net force, in the same direction as the net force, and inversely proportional to the mass of the object.

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Work is measured in _____.
DaniilM [7]

Answer:

work is measured in <u>joule</u><u>.</u><u> </u>

8 0
3 years ago
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What do you mean by unit lb
Bingel [31]

Unit lb mean pound. Which equals to about 0.45 kilograms(kg) /4536 grams,while 1kg equals to about 2.2lb.

Hope it helps!

7 0
3 years ago
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If the scaled-up man now stands on one leg, what fraction of the tensile strength is the stress on the femur?.
Firdavs [7]

The new cross sectional area and tensile stress is mathematically given as

A=4.8*10^{-4}m^2

X=14:100

<h3>Cross sectional area and stress on the femur</h3>

Question Parameters:

To see why this must be so, recall, that the stress on the femur for a man standing on one leg is 1.4%

we scale this man up by a factor of 10 in all dimensions

that a 70 kg person has a femur with a cross-section area

a)

Generally the New cross sectional area  is mathematically given as

100A=100*4.8*10^{-4}

A=4.8*10^{-4}m^2

b)

From the initial statement we see that  the fraction of the tensile strength is the stress on the femur  and will be

X=\frac{14}{100}

X=14$

X=14:100

For more information on fraction

brainly.com/question/1301963

Complete Question

Larger animals have sturdier bones than smaller animals. A mouse's skeleton is only a few percent of its body weight, compared to 16% for an elephant. To see why this must be so, recall, that the stress on the femur for a man standing on one leg is 1.4% of the bone's tensile strength. Suppose we scale this man up by a factor of 10 in all dimensions, keeping the same body proportions. (Assume that a 70 kg person has a femur with a cross-section area (of the cortical bone) of 4.8 x 10-4m², a typical value.)

Part A

Both the inside and outside diameter of the femur, the region of cortical bone, will increase by a factor of 10. What will be the new cross-section area? Express your answer using two significant figures.

Part B

If the scaled-up man now stands on one leg, what fraction of the tensile strength is the stress on the femur?

8 0
2 years ago
A mail carrier leaves the post office and drives 2.00 km to the north. He then drives in a direction 60.0° south of east for 7.00
den301095 [7]

Answer:

\theta=7^o

Explanation:

<u>Displacement</u>

It is a vector that points to the final point where an object traveled from its starting point. If the object traveled to several points, then the individual displacements must be added as vectors.

The mail carrier leaves the post office and drives 2 km due north. The first displacement vector is

\vec r_1=\ km

Then the carrier drives 7 km in 60° south of east. The displacement has two components in the x and y axis given by

\vec r_2=\ km=\ km

Finally, he drives 9.5 km 35° north of east.

\vec r_3=\ km=\ km

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\vec r_t=\ km

The direction can be calculated with

\displaystyle tan\theta=\frac{1.39}{11.28}=0.1232

\boxed{\theta=7^o}

7 0
3 years ago
The diagram shows a wave. The quantity shown is the amplitude. This quantity is directly proportional to which of these other qu
Katen [24]

As we know that frequency and wavelength are dependent on each other

and this is given by

f = \frac{c}{\lambda}

here we know that

\lambda = wavelength

f = frequency

c = speed of wave

while for energy and intensity of wave we know that

Energy = KA^2

here A = amplitude of wave

so energy directly depends on amplitude of wave

so correct answer will be

<em>A) Energy</em>

3 0
3 years ago
Read 2 more answers
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