Ask question

Ask question

All categories

marishachu [46]

3 years ago

10

A mail carrier leaves the post ofﬁce and drives 2.00 km to the north. He then drives in a direction 60.0° south of east for 7.00

km. After dropping off a package, he drives 9.50 km 35.0° north of east to Starbucks. What is the direction relative to the positive x axis?

1 answer:

den301095 [7]3 years ago

7 0

Answer:

$\theta=7^o$

Explanation:

<u>Displacement</u>

It is a vector that points to the final point where an object traveled from its starting point. If the object traveled to several points, then the individual displacements must be added as vectors.

The mail carrier leaves the post office and drives 2 km due north. The first displacement vector is

$\vec r_1=\ km$

Then the carrier drives 7 km in 60° south of east. The displacement has two components in the x and y axis given by

$\vec r_2=\ km=\ km$

Finally, he drives 9.5 km 35° north of east.

$\vec r_3=\ km=\ km$

The total displacement is

$\vec r_t=\ km+\ km+\ km$

$\vec r_t=\ km$

The direction can be calculated with

$\displaystyle tan\theta=\frac{1.39}{11.28}=0.1232$

$\boxed{\theta=7^o}$

You might be interested in

A machine part has the shape of a solid uniform sphere of mass 245 g and diameter 4.30 cm . It is spinning about a frictionless

Alla [95]

Answer:

Angular acceleration, $\alpha =9.49\ rad/s^2$

Explanation:

It is given that,

Mass of the solid sphere, m = 245 g = 0.245 kg

Diameter of the sphere, d = 4.3 cm = 0.043 m

Radius, r = 0.0215 m

Force acting at a point, F = 0.02 N

Let $\alpha$ is its angular acceleration. The relation between the angular acceleration and the torque is given by :

$\tau=I\times \alpha$

I is the moment of inertia of the solid sphere

For a solid sphere, $I=\dfrac{2}{5}mr^2$

$\alpha =\dfrac{\tau}{I}$

$\alpha =\dfrac{F.r}{(2/5)mr^2}$

$\alpha =\dfrac{5F}{2mr}$

$\alpha =\dfrac{5\times 0.02}{2\times 0.245\times 0.0215}$

$\alpha =9.49\ rad/s^2$

So, its angular acceleration is $9.49\ rad/s^2$ . Hence, this is the required solution.

3 0

3 years ago

What is the wavelength of an earthquake that shakes you with a frequency of 10.0 Hz and gets to another city 84.0 km away in 12.

Harrizon [31]

Answer:

700 m.

Explanation:

Wavelength: This can be defined as the distance in meter required by a wave to complete one oscillation. The S.I unit of of wavelength is meter (m).

the expression connecting velocity, frequency and wavelength is given as,

v = λf......................... Equation 1

Where v = velocity of the earthquake, λ = wavelength of the earthquake, f = frequency of the earthquake.

make λ the subject of the equation

λ = v/f ................. Equation 2

recall,

v = distance/time

v = d/t ................. Equation 2

Where d = distance, t -= time.

Given: d = 84 km = 84000 m, t = 12 s.

Substitute into equation 2

v = 84000/12

v = 7000 m/s.

Also given: f = 10 Hz.

Substitute into equation 2

λ = 7000/10

λ = 700 m.

Hence the wavelength of the earthquake = 700 m.

5 0

3 years ago

Read 2 more answers

A particle moves along the x axis according to the equation x = 6t², where x is in meters and t is in seconds. Therefore:

vladimir2022 [97]

Answer is E

time can be negative.
A is not true because <span>a=<span><span><span>d2</span>x</span><span>d<span>t2</span></span></span>=12 m/<span>s2</span></span>
C: question already said that particle move along x-axis, which is not parabola path.
D: velocity is <span><span><span>dx</span><span>dt</span></span>=12t</span>, therefore velocity changes by 12 m/s and not 9.8 m/s
So we are left with E. <span>
</span>

7 0

3 years ago

Spaceship 1 and Spaceship 2 have equal masses of 300 kg. Spaceship 1 has an initial momentum magnitude of 600 kg-m/s. What is it

kati45 [8]

Answer:

Initial speed of the spaceship 1, v = 2 m/s

Explanation:

Given that :

Mass of spaceship 1 and 2 that have equal mass are 300 kg

Initial momentum of the spaceship 1 is 600 kg-m/s

To find :

We need to find the initial momentum of spaceship 1.

Solve :

The momentum of an object is equal to the product of mass and its velocity. Its SI unit is kg-m/s. Mathematically, it is given by :

$p=mv$

$v=\dfrac{p}{m}$

$v=\dfrac{600\ kg-m/s}{300\ kg}$

v = 2 m/s

Therefore the initial speed of spaceship 1 is 2 m/s. Hence, this is the required solution.

6 0

3 years ago

A dog travels north for 18 meters, east for 8 meters, South for 27 meters and then west for 8 meters. What is the distance the d

Afina-wow [57]

I'm really not sure if this is right but I'll try.
The distance that the dog traveled is probably all of the distances added up. I would guess that it's 67 meters in total.
The displacement is a little more tricky but you pretty much have to put a mental map in your head. Since East and West are both 8 meters, they cancel each other out. He travels more southern and that means the displacement is 9 meters south of his original location

7 0

3 years ago