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3 years ago

In comparing an electric circuit to a roller coaster, which part of the roller coaster would be equivalent to a battery?

Physics

2 answers:

Natali [406]3 years ago

3 0

I guess it would have to be the engine that drags the coaster to the top of the first hill.

mina [271]3 years ago

3 0

So...its a question about energy transformation.
the rollarcoster is a example of energy transformation between kinetic energy and potential energy.while the battery is a transformation between chemical energy and electrical energy.that is some chemical reactions happen in the battery andtransform chemical energyv to electric energy:)

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Dimension of force of gravity is

statuscvo [17]

Answer:

$M^{-1}L^{3}T^{-2}$

Explanation:

Force has the unit N for Newton.

A Newton is $m*\frac{kg}{s^{2} }$ , mass*kilograms/seconds^2.

Dimensions in Physics include things such as Mass, Length, and Time.

kg is Mass

m is Length

s^2 is Time

So, since a Newton has all of these, it has T, L, and M. Force has dimensions $T^{-2}LM$

However, you must now consider gravitational force.

Law of Gravitation states:

$F=\frac{Gm_{1}m_{2}r }{r^{2} }$

Convert that into a fraction with dimensions:

$F=\frac{GM^{2} L}{L^{2} }$

Remember force is $T^{-2}LM$

Use the dimensions of force to find gravitational force, or G:

$F=\frac{GM^{2} L}{L^{2} }$

$T^{-2}LM=\frac{GM^{2} L}{L^{3} }$

$G=\frac{(T^{-2}LM)(L^{2}) }{M*M}$

$G=\frac{(T^{-2}L^{3} M) }{M^{2} }$

$G=M^{-1}L^{3}T^{-2}$

5 0

3 years ago

Is this right at all

Alja [10]

It is correct! good job :)

7 0

4 years ago

Define one newton force... No spam..

djverab [1.8K]

The force applied to make an object of mass 1 kg accelerate by 1 m/s² is equal to one newton.

8 0

2 years ago

Read 2 more answers

Why is the world round

zlopas [31]

The gravity pulls itself into a sphere also known as hydrostatic equilibrium. This gives the planet a sphere-like shape.

Hope that helps. -UF aka Nadia

8 0

3 years ago

At a distance of 41 ft , an ionizing radiation source delivers 5.0 rem of radiation. How close could you get to the source and s

mash [69]

Answer:

at distance 18.33 ft no biological effects

Explanation:

given data

distance = 41 ft

radiation = 5 rem

to find out

how close get so no biological effects

solution

we know here that intensity of radiation R is inversely proportional to (radiation)²

so here equation will be

$\frac{I1}{I2} = (\frac{R2}{R1})^{2}$ .............1

here I is intensity

so here I1 = 25

because for 0 to 25 there is no detectable effects and for 25 to 100 it will . temporary decrease so

we take 25 because dose is less than 25 so we take that highest value

$\frac{I1}{I2} = (\frac{R2}{R1})^{2}$

$\frac{25}{5} = (\frac{41}{R1})^{2}$

R1 = 18.33 ft

so at distance 18.33 ft no biological effects

6 0

3 years ago