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3 years ago

In comparing an electric circuit to a roller coaster, which part of the roller coaster would be equivalent to a battery?

Physics

2 answers:

Natali [406]3 years ago

3 0

I guess it would have to be the engine that drags the coaster to the top of the first hill.

mina [271]3 years ago

3 0

So...its a question about energy transformation.
the rollarcoster is a example of energy transformation between kinetic energy and potential energy.while the battery is a transformation between chemical energy and electrical energy.that is some chemical reactions happen in the battery andtransform chemical energyv to electric energy:)

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Two sound waves, from two different sources with the same frequency of 420 Hz travel in the same direction at 336 m/s. The sourc

Tresset [83]

Answer:

Pi(3.14) radians or 180º degrees

Explanation:

First of all, we need to obtain the wavelength of a wave traveling to the speed of sound and 420 Hz of frequency.

The formula is:

$l=wavevelocity/frequency$

where l = wavelength in meters

With current values:

l = 336 [m/s]/420[1/s] = 0.8 meters

Since a complete cycle (360º or 2pi radians) needs 0.8 meters to complete, 0.4 meters or 40 cm is just half of it, making a 180º degree phase or 3.14 radians.

8 0

3 years ago

the speed of a train is decreased in a uniform rate from 96 km/h to 48km/h through a distance of 800m. calculate the distance co

GREYUIT [131]

Answer:

1066.67 m

Explanation:

Given:

v₀ = 96 km/h = 26.67 m/s

v = 48 km/h = 13.33 m/s

Δx = 800 m

Find: a

v² = v₀² + 2aΔx

(13.33 m/s)² = (26.67 m/s)² + 2a (800 m)

a = -0.333 m/s²

Given:

v₀ = 26.67 m/s

v = 0 m/s

a = -0.333 m/s²

Find: Δx

v² = v₀² + 2aΔx

(0 m/s)² = (26.67 m/s)² + 2 (-0.333 m/s²) Δx

Δx = 1066.67 m

Round as needed.

7 0

3 years ago

A circular coil of wire, with N turns of radius a, is located in the field of an electromagnet. The magnetic field is perpendicu

weeeeeb [17]

Answer:

they are going to attract

Explanation:

7 0

3 years ago

Two small plastic spheres are given positive electrical charges. When they are a distance of 14.8cm apart, the repulsive force b

sdas [7]

Answer:

Explanation:

Case I: They have same charge.

Charge on each sphere = q

Distance between them, d = 14.8 cm = 0.148 m

Repulsive force, F = 0.235 N

Use Coulomb's law in electrostatics

$F=\frac{Kq_{1}q_{2}}{d^{2}}$

By substituting the values

$0.235=\frac{9\times10^{9}q^{2}}{0.148^{2}}$

$q=7.56\times10^{-7}C$

Thus, the charge on each sphere is $q=7.56\times10^{-7}C$ .

Case II:

Charge on first sphere = 4q

Charge on second sphere = q

distance between them, d = 0.148 m

Force between them, F = 0.235 N

Use Coulomb's law in electrostatics

$F=\frac{Kq_{1}q_{2}}{d^{2}}$

By substituting the values

$0.235=\frac{9\times 10^{9}\times 4q^{2}}{0.148^{2}}$

$q=3.78\times10^{-7}C$

Thus, the charge on second sphere is $q=3.78\times10^{-7}C$ and the charge on first sphere is $4q = 4\times 3.78\times 10^{-7}=1.51 \times 10^{-6} C$ .

6 0

4 years ago

How can Ethan best defend his conclusion?

nirvana33 [79]

The defense that Ethan should choose is going to depend heavily
on what his conclusion is.

4 0

4 years ago