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Fynjy0 [20]
3 years ago
8

An autographed baseball rolls off of a 0.91 m high desk and strikes the floor 0.84 m away from the desk. How fast was it rolling

on the desk before it fell off? The acceleration of gravity is 9.81 m/s2 .
Physics
1 answer:
Rudik [331]3 years ago
4 0
The initial velocity (its speed before falling off) is approximately 1.95 m/s
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Cosine law can be applied when .....................
jarptica [38.1K]

Answer:

<em>Two</em><em> </em><em>sides</em><em> </em><em>and</em><em> </em><em>angle</em><em> </em><em>between</em><em> </em><em>them</em><em> </em><em>is</em><em> </em><em>given</em><em> </em>

3 0
2 years ago
the olympic swimmer swims to the end of the 50 m pool and back 4 times. calculate the distance covered.
Ludmilka [50]

Answer:

400 m

Explanation:

The swimmer swims 50 meters to one end of the pool but has to swim back therefore you double 50 which would be 100 meters. Then you have to multiply 100 by 4 since the swimmer did it 4 times.

7 0
3 years ago
Write down an equation describing a sinusoidal traveling wave (in 1-D). Tell us (words and/or equations) what in your equation t
Natalija [7]

Answer:

Explanation:

The standard equation of the sinusoidal wave in one dimension is given by

y = A Sin\left ( \frac{2\pi }{\lambda }\left ( vt-x \right )+\phi  \right )

Here, A be the amplitude of the wave

λ be the wavelength of the wave

v be the velocity of the wave

Φ be the phase angle

x be the position of the wave

t be the time

this wave is travelling along positive direction of X axis

The frequency of wave is f which relates with velocity and wavelength as given below

v = f x λ

The relation between the time period and the frequency is

f = 1 / T.

6 0
3 years ago
Two large non-conducting plates of surface area A = 0.25 m 2 carry equal but opposite charges What is the energy density of the
Stells [14]

Answer:

5.1*10^3 J/m^3

Explanation:

Using E = q/A*eo

And

q =75*10^-6 C

A = 0.25

eo = 8.85*10^-12

Energy density = 1/2*eo*(E^2) = 1/2*eo*(q/A*eo)^2 = [q^2] / [2*(A^2)*eo]

= [(75*10^-6)^2] / [2*(0.25)^2*8.85*10^-12]

= 5.1*10^3 J/m^3

8 0
3 years ago
The area in which the attraction and the repulsion of a magnet's poles are felt is a(n)
docker41 [41]

The are is called a magnetic field.


8 0
3 years ago
Read 2 more answers
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