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scZoUnD [109]
3 years ago
6

A bird flies directly into the windshield of a moving car. How does the FORCE exerted on the car compare to the FORCE exerted on

the bird?
A: the force on the car is less than the force on the bird
B: The force on the car is equal to the force on the bird
C: the force on the car is greater than the force on the bird
Physics
1 answer:
Anarel [89]3 years ago
7 0

Answer:

b

Explanation:

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Is being social media famous worth real-life relationships?
Maru [420]

Answer:

No

Explanation:

Social media fame isnt worth it, because youre not really able to connect with people. Real life relationships with friends, family, and everything else is way more important. having people notice you or be attracted to you through the internet is nothing compared to real life social interactions. Dont leave people just to be online, youre going to regret it.

3 0
3 years ago
to move a resting box of 100 Newton on the ground with kinetic friction coeficient of 0,250 is applied a force of 60 N horizonta
krok68 [10]
Work is calculated by multiplying force by the distance that the object had moved. The applied force is 60 N, moving the object by 10 m. Thus, the work does is 600 J. For the friction force which is equal to,
                          100N x 0.250 = 25.0 N
the work done is,
                        W = (60 N - 25 N) x 10 m = 350 J
The kinetic energy of the box can be equated to this force. Thus, the answer is also 350 J. 
6 0
3 years ago
How far will an object move in one second if it average speed is 5m/s?
Sphinxa [80]

The object will move 5 meters per second (5m/s)

3 0
3 years ago
Read 2 more answers
A basketball leaves a player's hands at a height of 2.00 m above the floor. The basket is 3.05 m above the floor. The player lik
shutvik [7]

Answer:(10.69, 11.436)

Explanation:

Given

initial height of ball is 2 m

height of basket is 3.05 m

Launching angle=40^{\circ}

x =12\pm 0.27

y=1.05

equation of trajectory of ball is given by

y=xtan\theta -\frac{gx^2}{2u^2cos^2\theta }

for x=12.27

1.05=12.27\times tan40-\frac{g12.27^2}{2u^2cos^{2}40 }

u=10.69

for x=11.73

1.05=11.73\times tan40-\frac{g11.73^2}{2u^2cos^{2}40 }

u=11.436 m/s

Thus range of speed is (10.69, 11.436)

3 0
2 years ago
Both high-side pressures and low-side pressures are low with the engine running and the selector set to the air-conditioning pos
elena-14-01-66 [18.8K]

Answer:

Technician A only

Explanation:

Both high-side pressures and low-side pressures are low with the engine running and the selector set to the air-conditioning position. Technician A says that the system is undercharged. Technician B says the cooling fan could be inoperative. Which technician is correct?

usually . An overcharged system will result in lower than normal low side pressures

An undercharged system will not enable  the compressor  to create pressure. As a result of the low amount of refrigerant, the cooling ability is reduced. When we say undercharged, we mean the refrigerant in the system is low, so the both the high side pressures and low side pressures will be low.

8 0
2 years ago
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