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scZoUnD [109]
3 years ago
6

A bird flies directly into the windshield of a moving car. How does the FORCE exerted on the car compare to the FORCE exerted on

the bird?
A: the force on the car is less than the force on the bird
B: The force on the car is equal to the force on the bird
C: the force on the car is greater than the force on the bird
Physics
1 answer:
Anarel [89]3 years ago
7 0

Answer:

b

Explanation:

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Two forces one of 12N and another of 5N act on a body in such away that they makes an angle of 90 digre with each other,what is
ELEN [110]

Answer:

Sorry I didn't know the answer

6 0
3 years ago
A box slides down a 31° ramp with an acceleration of 0.99 m/s2. Determine the coefficient of kinetic friction between the box an
tino4ka555 [31]

Answer:\mu=0.48

Explanation:

Given

inclination \theta =31^{\circ}

Acceleration of object=0.99 m/s^2

Now using FBD

mg\sin \theta -f_r=ma

mg\sin \theta -\mu mg\cos \theta =ma

a=g\sin \theta -\mu g\cos \theta

0.99=5.04-\mu 8.4

\mu 8.4=4.057

\mu =0.48

7 0
3 years ago
A capacitor C is fully charged by connecting it to battery of V Volt. Then it is disconnected from battery. If the separation be
vodomira [7]

Answer:

Explanation:

i )

When it is disconnected with the battery , the charge stored in it becomes fixed . When the plate distance becomes half , its capacitance becomes twice from C to 2C . Let charge stored in it at the time of disconnection from battery be Q . Let plate separation reduces from d to d / 2

So charged stored in it will remain unchanged .

ii )

Potential difference = charge / capacitance

in the first case potential difference = Q / C

in the second case potential difference = Q / 2C

So potential difference becomes half .

iii ) electric field = potential diff / plate separation

in the first case electric field = Q / (d x C )

in the second case electric field = 2 Q / (d x 2C)

= Q / (d  x C )

So electric field remains unchanged .

iv)

energy stored in first case = Q² / 2C

In the second case energy stored = Q² / 2x2C

so energy stored becomes half .

4 0
3 years ago
Potassium ions (K+) move across a 7.0 -mm- thick cell membrane from the inside to the outside. The potential inside the cell is
Reil [10]

Explanation:

Relation between potential energy and charge is as follows.

           U = qV

or,    \Delta U = q \times \Delta V

                   = 1.6 \times 10^{-19} \times 70 \times 10^{-3}

                   = 112 \times 10^{-22} J

or,                = 1.12 \times 10^{20} J

Therefore, we can conclude that change in the electrical potential energy \Delta U is 1.12 \times 10^{20} J.

7 0
3 years ago
What's the time constant of a 10 H inductor and a 200 ohm resistor connected in series
melamori03 [73]
<h3>Option B</h3><h3>The time constant of a 10 H inductor and a 200 ohm resistor connected in series is 50 millisecond</h3>

<em><u>Solution:</u></em>

Given that,

10 H inductor and a 200 ohm resistor connected in series

To find: time constant

<em><u>The time constant in seconds is given as:</u></em>

Time\ constant = \frac{L}{R}

Where,

L is the inductance in henry and R is the resistance in ohms

Time\ constant = \frac{10}{200}\\\\Time\ constant = 0.05\ seconds

Convert to millisecond

1 second = 1000 millisecond

0.05 second = 0.05 x 1000 = 50 millisecond

Thus time constant is 50 millisecond

7 0
3 years ago
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