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dalvyx [7]
2 years ago
10

QUESTION 9 of 10: You enter a bid. Your cost on the product you make is $112 per unit. If you bid at $138 per unit, what percent

is the price
you bid over your cost? (Round to the nearest percent)
O a) 19%
Ob) 23%
O c) 81%
Mathematics
2 answers:
Oksana_A [137]2 years ago
7 0

I would say B as the answer... 81 is just to high and 19 doesn't seem right.. so I'm just gonna go with B 23%

I am very sorry if this is wrong in anyway!

Paraphin [41]2 years ago
3 0

Answer:

the answer is 23%

Step-by-step explanation:

i used a percent increase calc... was too lazy to do the work haha

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(b) Three objects are brought close to each other, two at a time. When objects A and B are brought together, they repel. When ob
zheka24 [161]

Answer:

Step-by-step explanation:

When A and B are brought together then they repel i.e. A and B have same charge, either negative or positive

When B and C are brought together then they also repel. This implies that nature of charge on  B and C is same          

4 0
3 years ago
Please help me with this problem i need this now
Bad White [126]

Answer:

$2,975

Step-by-step explanation:

Discount = Original Price x Discount %/100

Discount = 3500 × 15/100

Discount = 3500 x 0.15

You save = $525.00

Final Price = Original Price - Discount

Final Price = 3500 - 525

Final Price = $2,975.00

4 0
2 years ago
How many sequences of 0s and 1s of length 19 are there that begin with a 0, end with a 0, contain no two consecutive 0s, and con
sladkih [1.3K]

65 sequences.

Lets solve the problem,

The last term is 0.

To form the first 18 terms, we must combine the following two sequences:

0-1 and 0-1-1

Any combination of these two sequences will yield a valid case in which no two 0's and no three 1's are adjacent

So we will combine identical 2-term sequences with identical 3-term sequences to yield a total of 18 terms, we get:

2x + 3y = 18

Case 1: x=9 and y=0

Number of ways to arrange 9 identical 2-term sequences = 1

Case 2: x=6 and y=2

Number of ways to arrange 6 identical 2-term sequences and 2 identical 3-term sequences =8!6!2!=28=8!6!2!=28

Case 3: x=3 and y=4

Number of ways to arrange 3 identical 2-term sequences and 4 identical 3-term sequences =7!3!4!=35=7!3!4!=35

Case 4: x=0 and y=6

Number of ways to arrange 6 identical 3-term sequences = 1

Total ways = Case 1 + Case 2 + Case 3 + Case 4 = 1 + 28 + 35 + 1 = 65

Hence the number of sequences are 65.

Learn more about Sequences on:

brainly.com/question/12246947

#SPJ4

8 0
2 years ago
5 more than the product of a number and 4 is equal to 3 use variable y for unknown number
Inessa05 [86]

Answer:

(y + 4) + 5 = 3 \\ y + 9 = 3 \\ y =  - 6 \\

I'm not sure

8 0
3 years ago
Is the following function an even function, odd function, or neither?
expeople1 [14]

Answer:

I think neither but i suggest you not take my word for it.

Step-by-step explanation:

3 0
3 years ago
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