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2 years ago

11

Shawna's school tennis team is running a car wash this weekend. They will charge $13 per

1 answer:

konstantin123 [22]2 years ago

6 0

Answer:

:)

Step-by-step explanation:

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Andreas93 [3]

Answer:

480

Step-by-step explanation:

3 0

2 years ago

I need help,Please it’s due today

Andrej [43]

Answer: Sorry, I’m lazy today so I’ll just answer the first question, letter a. The answer is 30 cups of red paint.

Step-by-step explanation: Since you need 2 cups of blue paint and 4 cups of red paint, the ratio of the amount of cups you need for each paint is 1 cup of blue for every 2 cups of red. You need 15 cups of blue so you multiply it by 2 and you get 30. I hope this wasn’t confusing and I hope this helps. Please listen to you teacher because it would really help you on your work.

7 0

2 years ago

This table shows values represented by an exponential function.

Bad White [126]

Answer:

$a = 2 , f(2)=9$

$b = 4 , f(4)=64$

And replacing the data into the average rate formula we got:

$m = \frac{64-9}{4-2}= 27.5$

And then the best answer for this case would be:

C. 27.5

Step-by-step explanation:

For this cae we know that the average rate of change of a function is given by this general expresion:

$m = \frac{f(b) -f(a)}{b-a}$

For this special case from the info of the table we have:

$a = 2 , f(2)=9$

$b = 4 , f(4)=64$

And replacing the data into the average rate formula we got:

$m = \frac{64-9}{4-2}= 27.5$

And then the best answer for this case would be:

C. 27.5

7 0

3 years ago

When jack went to the movie he paid $8 for his popcorn and $4 for each additional order of popcorn. if i represents the total co

melamori03 [73]

I = 8 + 4x

XD That's expensive popcorn!

8 0

3 years ago

Read 2 more answers

If n is a positive integer, how many 5-tuples of integers from 1 through n can be formed in which the elements of the 5-tuple ar

erma4kov [3.2K]

Answer:

$\frac{(n+4)*(n+3)*(n+2)*(n+1)*n}{120}$

Step-by-step explanation:

Given

5 tuples implies that:

$n = 5$

$(h,i,j,k,m)$ implies that:

$r = 5$

Required

How many 5-tuples of integers $(h, i, j, k,m)$ are there such that $n\ge h\ge i\ge j\ge k\ge m\ge 1$

From the question, the order of the integers h, i, j, k and m does not matter. This implies that, we make use of combination to solve this problem.

Also considering that repetition is allowed: This implies that, a number can be repeated in more than 1 location

So, there are n + 4 items to make selection from

The selection becomes:

$^{n}C_r => ^{n + 4}C_5$

$^{n + 4}C_5 = \frac{(n+4)!}{(n+4-5)!5!}$

$^{n + 4}C_5 = \frac{(n+4)!}{(n-1)!5!}$

Expand the numerator

$^{n + 4}C_5 = \frac{(n+4)!(n+3)*(n+2)*(n+1)*n*(n-1)!}{(n-1)!5!}$

$^{n + 4}C_5 = \frac{(n+4)*(n+3)*(n+2)*(n+1)*n}{5!}$

$^{n + 4}C_5 = \frac{(n+4)*(n+3)*(n+2)*(n+1)*n}{5*4*3*2*1}$

$^{n + 4}C_5 = \frac{(n+4)*(n+3)*(n+2)*(n+1)*n}{120}$

<u><em>Solved</em></u>

6 0

2 years ago