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3 years ago

8

(X-2)(3x-4) help on this please show your work?

2 answers:

Ganezh [65]3 years ago

6 0

Assuming you want to expand the equation:
Foil the equation (first, outer, inner, last).

First:
x*3x= 3x^2

Outer:
x*-4=-4x

Inner:
-2*3x=-6x

Last:
-2*-4=8

Put it all together and simplify like terms.
3x^2-4x-6x+8
3x^2-10x+8

Final answer: 3x^2-10x+8

If you want root, apply the Zero Product Property.
(x-2)=0
x=2

(3x-4)=0
3x=4
x=4/3

Final answer: x=2, x=4/3

andrezito [222]3 years ago

5 0

(x-2)(3x-4)
= (x)(3x) + (x)(-4) + (-2)(3x) + (-2)(-4)
= 3x² + (-4x) + (-6x) + 8
= 3x² - 4x - 6x + 8
= 3x² - 10x + 8

I'm not sure so yeah :3

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jolli1 [7]

Answer:

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Step-by-step explanation:

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3 years ago

Philip shoots an arrow from the top of a hill into the ground. the flight of the arrow can be modeled with the quadratic functio

Sati [7]

Answer:

(a)Time taken to reach the ground, x=6 seconds

(b)Maximum height of the arrow during its flight =101.25 feet

Step-by-step explanation:

Given the quadratic function which models the flight of the arrow:

$y=-5x^2+15x+90$

Where:

y represents the vertical height of the arrow, in meters; and
x represents the time, in seconds.

(a)Positive Zero

$-5x^2+15x+90=0\\-5(x^2-3x-18)=0\\-5(x^2-6x+3x-18)=0\\-5(x(x-6)+3(x-6))=0\\-5(x+3)(x-6)=0\\x+3=0\:or\:x-6=0\\x=-3,x=6$

In 6 seconds, the arrow will hit the horizontal plane, i.e. the ground.

(b)

$y=-5x^2+15x+90\\y-90=-5(x^2-3x)\\y-90-5(\frac{9}{4}) =-5(x^2-3x+(\frac{3}{2} )^2)\\y-101.25=-5(x-\frac{3}{2} )^2\\y=-5(x-\frac{3}{2} )^2+101.25$

Comparing with the vertex form:

$y=a(x-h)^2+k$

Our vertex, (h,k)=(1.5, 101.25)

Maximum Value of y=101.25

The maximum value of y represents the maximum height of the arrow during its flight, which is 101.25 feet.

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4 years ago

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Answer:

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Since production cannot be negative, revenue will be at a maximum when x = 35, or when the production level is 35,000 units.

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Answer:

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