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Shkiper50 [21]
3 years ago
8

(X-2)(3x-4) help on this please show your work?

Mathematics
2 answers:
Ganezh [65]3 years ago
6 0
Assuming you want to expand the equation:
Foil the equation (first, outer, inner, last).

First:
x*3x= 3x^2

Outer:
x*-4=-4x

Inner:
-2*3x=-6x

Last:
-2*-4=8

Put it all together and simplify like terms.
3x^2-4x-6x+8
3x^2-10x+8

Final answer: 3x^2-10x+8

If you want root, apply the Zero Product Property.
(x-2)=0
x=2

(3x-4)=0
3x=4
x=4/3

Final answer: x=2, x=4/3
andrezito [222]3 years ago
5 0
   (x-2)(3x-4)
= (x)(3x) + (x)(-4) + (-2)(3x) + (-2)(-4)
= 3x² + (-4x) + (-6x) + 8
= 3x² - 4x - 6x + 8
= 3x² - 10x + 8

I'm not sure so yeah :3
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Answer:

The spaceship will get to Alpha Centaur in time

Step-by-step explanation:

<u><em>The complete question in English is</em></u>

You're the commander of a spaceship. Your mission is to reach Alpha Centaur  in five years. The distance from the sun to Alpha Centaur is 2.5 x 10^13 miles. The distance  from Earth to Sun is approximately 9.3 x 10^7

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Find the time it takes for the spaceship to travel from Earth to the Sun

The distance from the Earth to Sun is equal to

9.3*10^7\ miles

The spaceship can travel  at the speed of light

The light can travel a distance of 5.88*10^{12}\ miles in a year

so

using a proportion

\frac{5.88*10^{12}\ miles}{1\ year}=\frac{9.3*10^7\ miles}{x}\\\\x=(9.3*10^7)/5.88*10^{12}\\\\x=1.58*10^{-5} \ years

This time is very small in years

Convert to minutes

1.58*10^{-5} \ years=1.58*10^{-5} (365)(24)(60)=8.3\ min

step 2

Find the time it takes for the spaceship to travel from the Sun to Alpha Centaur

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The spaceship can travel  at the speed of light

The light can travel a distance of 5.88*10^{12}\ miles in a year

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\frac{5.88*10^{12}\ miles}{1\ year}=\frac{2.5*10^{13}\ miles}{x}\\\\x=(2.5*10^{13})/5.88*10^{12}\\\\x=4.25\ years

4.25\ years< 5\ years

therefore

The spaceship will get to Alpha Centaur in time

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