Answer:
<h3><ABC > <DBC.</h3>
Step-by-step explanation:
Given < DBC = < RST and we need to prove < ABC is greater than <RST.
First given statement:
< DBC = < RST
Reason: Given.
Second given statement :
<ABC = <DBC+ <ABD.
Reason: Angle addition theorem.
<em>Note: < ABC is the sum of angles <DBC and <ABD and we have < DBC = < RST. So it's an obvious thing that the sum of angles <DBC and <ABD is always greater than <RST.</em>
Also, <ABC is greater than <DBC.
Therefore, correct option for third statement is :
<h3><ABC > <DBC.</h3>
X=1/2
Could be your answer
Answer: Addition Property of Equality
We add 7 to both sides to go from 19 = 2x-7 to 26 = 2x
Answer:
B=23.19
Step-by-step explanation:
First, find the last side of the triangle using the Pythagorean theorem.
![a^{2} +b^{2} =c^{2} \\21^{2} +9^{2} =c^{2} \\441+81=c^{2} \\\sqrt[3]{58}=c](https://tex.z-dn.net/?f=a%5E%7B2%7D%20%2Bb%5E%7B2%7D%20%3Dc%5E%7B2%7D%20%5C%5C21%5E%7B2%7D%20%2B9%5E%7B2%7D%20%3Dc%5E%7B2%7D%20%5C%5C441%2B81%3Dc%5E%7B2%7D%20%5C%5C%5Csqrt%5B3%5D%7B58%7D%3Dc)
Then, find the missing angle, lets name it B.
The angle B can be found using the inverse sine function.
B=arcsin(opp/hyp)
![B=arcsin(\frac{9}{\sqrt[3]{58} } )\\B=23.19](https://tex.z-dn.net/?f=B%3Darcsin%28%5Cfrac%7B9%7D%7B%5Csqrt%5B3%5D%7B58%7D%20%7D%20%29%5C%5CB%3D23.19)
Step-by-step explanation:
if they are parralel it means gradient is the same
finding equation we find another point which is (x,y)
therefore y - 2/ x - 4 should be equal to 2/3.
y - 2 = 2/3(x - 4)
y - 2 = 2/3x - 8/3
y = 2/3x - 8/3 + 2
